#include #define rep(i,n) for(int i = 0; i < (n); i++) using namespace std; typedef long long ll; int main(){ cin.tie(0); ios::sync_with_stdio(0); int N,D,K; cin >> N >> D >> K; int dp[N + 1][D + 1][K + 1] = {}; dp[0][0][0] = 1; for(int n = 1; n <= N; n++) { for(int d = 0; d <= D; d++) { for(int k = 0; k <= K; k++) { int x = N + 1 - n; if(d + x <= D && k + 1 <= K) dp[n][d + x][k + 1] |= dp[n - 1][d][k]; dp[n][d][k] |= dp[n - 1][d][k]; } } } if(!dp[N][D][K]){ cout << -1 << endl; return 0; } int n = N, d = D, k = K; vector ans = {0}; while(d > 0) { int ok = 0; for(int x = ans.back() + 1; x <= N; x++) { if(dp[n - 1][d - x][k - 1]) { ans.push_back(x); n -= 1; d -= x; k -= 1; ok = 1; break; } } if(!ok) break; } ans.erase(ans.begin()); for(int a : ans) cout << a << " "; cout << endl; }