#include using namespace std; //#pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,1,0,-1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } void solve(ll n,ll m,vl v,vvl g){ vvl dp(n,vl(2,-INF));dp[0][0]=0; rep(i,n){ for(auto p:g[i]){ if(v[i]-v[p]>0)chmax(dp[i][1],dp[p][0]+v[i]-v[p]); else { chmax(dp[i][0],dp[p][0]); chmax(dp[i][0],dp[p][1]); } } } ll f=max(dp[n-1][0],dp[n-1][1]); cout << (f<0? -1:f) << endl; } int main(){ ll n,m;cin >> n >> m; vl v(n);rep(i,n)cin >> v[i]; vvl g(n),rg(n); rep(i,m){ ll a,b;cin >> a >> b;a--;b--; g[b].emplace_back(a); rg[n-1-a].emplace_back(n-1-b); } solve(n,m,v,g); rev(all(v)); solve(n,m,v,rg); }