#include //#include using namespace std; //using namespace atcoder; //using mint = modint1000000007; //const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; //const int INF = 1e9; //const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define endl "\n" #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; long long mod1 = 1000000007; long long mod2 = 998244353; int kind = 27; vectortable1(1000006), table2(100006); table1[0] = 1, table2[0] = 1; rep2(i, 1, table1.size()) { table1[i] = (table1[i - 1] * kind) % mod1; table2[i] = (table2[i - 1] * kind) % mod2; } setst1, st2; rep(i, n) { string s; cin >> s; long long base1 = 0; long long base2 = 0; rep(j, s.size()) { base1 += table1[j] * (s[j] - 'a' + 1); base1 %= mod1; base2 += table2[j] * (s[j] - 'a' + 1); base2 %= mod2; } bool chk = false; if (st1.count(base1) && st2.count(base2))chk = true; rep(j, s.size() - 1) { long long val1 = base1; val1 += mod1 - table1[j + 0] * (s[j + 0] - 'a' + 1) % mod1; val1 += mod1 - table1[j + 1] * (s[j + 1] - 'a' + 1) % mod1; val1 += table1[j + 0] * (s[j + 1] - 'a' + 1); val1 += table1[j + 1] * (s[j + 0] - 'a' + 1); val1 %= mod1; long long val2 = base2; val2 += mod2 - table2[j + 0] * (s[j + 0] - 'a' + 1) % mod2; val2 += mod2 - table2[j + 1] * (s[j + 1] - 'a' + 1) % mod2; val2 += table2[j + 0] * (s[j + 1] - 'a' + 1); val2 += table2[j + 1] * (s[j + 0] - 'a' + 1); val2 %= mod2; if (st1.count(val1) && st2.count(val2))chk = true; } if (chk)cout << "Yes" << endl; else cout << "No" << endl; st1.insert(base1); st2.insert(base2); } return 0; }