#include using namespace std; //#pragma GCC optimize("Ofast") #define rep(i,n) for(ll i=0;i=0;i--) #define perl(i,r,l) for(ll i=r-1;i>=l;i--) #define fi first #define se second #define pb push_back #define ins insert #define pqueue(x) priority_queue,greater> #define all(x) (x).begin(),(x).end() #define CST(x) cout<> #define rev(x) reverse(x); using ll=long long; using vl=vector; using vvl=vector>; using pl=pair; using vpl=vector; using vvpl=vector; const ll MOD=1000000007; const ll MOD9=998244353; const int inf=1e9+10; const ll INF=4e18; const ll dy[9]={1,0,-1,0,1,1,-1,-1,0}; const ll dx[9]={0,1,0,-1,1,-1,1,-1,0}; template inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; } ll m; void solve(string s){ ll ans=0; ll p=9; repl(i,1,s.size()){ ans+=p;ans%=m; if(i%2==0)p=p*10%m; } ll now=0; ll f=0; rep(i,(s.size()+1)/2){ now*=10; f*=10; if(i==0)f+=1; now+=s[i]-'0'; now%=m; f%=m; } ans=(now+ans-f+m)%m; string t; string ref; t=s.substr(0,(s.size()+1)/2); ref+=t;if(s.size()&1)t.pop_back(); rev(all(t));ref+=t; //cout << ref << endl; if(ref<=s)ans++; cout << ans%m << endl; } int main(){ string s;cin >> s; m=1e9; solve(s); m+=7; solve(s); }