#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
//using mint = modint1000000007;
//const int mod = 1000000007;
using mint = modint998244353;
const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }

int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int c, x; cin >> c >> x;

	if (0 == x) {
		mint ans = (mint)1 / (c + 1);
		cout << ans.val() << endl;
		return 0;
	}
	if (x <= c) {
		mint ans = (mint)(x) / (x + 1);
		cout << ans.val() << endl;
		return 0;
	}
	vector dp(x - c + 1, vector<mint>(x + 1, 0));
	dp[0][0] = 1;
	vector<mint>inv(x + 1);
	rep2(i, 1, x + 1)inv[i] = ((mint)i).inv();
	rep(i, x - c) {
		rep(j, x) {
			dp[i + 1][j + 0] += dp[i][j] * j *inv[c + i + 1];
			dp[i + 1][j + 1] += dp[i][j] * (c + i + 1 - j) *inv[c + i + 1];
		}
	}
	mint ans = 0;
	rep(i, x + 1) {
		mint sub = dp[x - c][i];
		sub *= x - i;
		sub *= inv[x - i + 1];
		ans += sub;
	}
	cout << ans.val() << endl;
	return 0;
}