from functools import reduce
from math import log10, floor
from operator import mul

digit_pattern = {"0": 1, "1": 1, "2": 1, "3": 2, "4": 2, "5": 2, "6": 3,
                 "7": 3, "8": 3, "9": 4}


def main():
    N = int(input())
    if N < 12:
        print(0)
        return
    if N < 100:
        print((N - 12) // 3 + 1)
        return

    two_digit = 18

    over_two_digit = 4 ** floor(log10(N)) - 4

    last_digit = 0
    if int(str(N)[0]) == 3:
        last_digit = reduce(mul, map(digit_pattern.get, str(N)[1:]))
    elif 3 < int(str(N)[0]) < 6:
        last_digit = 4 ** floor(log10(N))
    elif int(str(N)[0]) == 6:
        last_digit = (reduce(mul, map(digit_pattern.get, str(N)[1:]))
                      + 4 ** floor(log10(N)))
    elif 6 < int(str(N)[0]) < 9:
        last_digit = 2 * 4 ** floor(log10(N))
    elif int(str(N)[0]) == 9:
        last_digit = (reduce(mul, map(digit_pattern.get, str(N)[1:]))
                      + 2 * 4 ** floor(log10(N)))

    print(two_digit + over_two_digit + last_digit)


if __name__ == "__main__":
    main()