#include #include #define rep(i,b) for(int i=0;i=0;i--) #define rep1(i,b) for(int i=1;i=x;i--) #define fore(i,a) for(auto i:a) #define fore1(i,a) for(auto &i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template using mpq = priority_queue, greater>; template bool chmax(T &a, const T &b) { if (a bool chmin(T &a, const T &b) { if (b ll sumv(const vector&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define dame { cout << "No" << endl; return;} #define dame1 { cout << -1 << endl; return;} #define deb(x,y) cout << x << " " << y << endl; #define debp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define countv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair;using pil = pair;using pli = pair;using pii = pair;using pdd = pair; using tp = tuple; using vi = vector;using vd = vector;using vl = vector;using vs = vector;using vb = vector; using vpii = vector;using vpli = vector;using vpll = vector;using vpil = vector; using vvi = vector>;using vvl = vector>;using vvs = vector>;using vvb = vector>; using vvpii = vector>;using vvpli = vector>;using vvpll = vector;using vvpil = vector; using mint = modint998244353; using vm = vector; using vvm = vector>; vector dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<= LLONG_MAX/a) break; tmp *= a; ret++; } ret--; return ret; } ll pow(ll x , ll a){ assert(x > 0); assert(a >= 0); ll ret = 1; rep(_,a){ assert (ret < LLONG_MAX/x); ret *= x; } return ret; } ll base(ll x,int a){ ll ans=0,y; for (ll i=0;x>0;i++){ y = x/a; ans += (x - y*a)*pow(10,i); x = y; } return ans; } string baseS(ll x,int a){ string ans; ll y; for (ll i=0;x>0;i++){ y = x/a; ans += '0' + (x - y*a); x = y; } reverse(rng(ans)); return ans; } ll inv(vl& v){ int n = sz(v); map mp; fore(y,v) mp[y] = 0; int m = 0; fore1(y,mp) y.se = m++; fenwick_tree fw(m); ll ret = 0; rep(i,n){ int k = mp[v[i]]; ret += fw.sum(k+1,m); fw.add(k,1); } return ret; } } math; // .div.mul : div[i]、mul[i]はそれぞれiの約数、倍数を格納している。 // .div_init(n) : div,mulを初期化。引数はnまで。n < 1e6 ~ 1e7。 // .divisor(x) : xの約数列挙。xは64bit整数。 // .sqrt(x) : floor(sqrt(x))。xは64bit整数。誤差は発生しない。 // .logx(x , a) : floor(loga(x))。xは64bit整数。誤差は発生しない。 // .pow(x , a) : x^a。誤差は発生しない。 // .base(x , a) : x(10進数)をa進数表記に。1 <= a <= 10。戻り値はll型。 // .baseS(x , a) : x(10進数)をa進数表記に。1 <= a <= 10。戻り値はstring型。 // .inv(v) : vの転倒数。 void solve(){ ll n,m; cin>>n>>m; mint ans = mint(n)*(n+1)/2 * m; chmin(m,n); mint sum = 0; ll c = (ll)sqrt(n); ll now = m; int nowi = -1; vl d; ll pre = 0; for(int i=1;i*i<=n;i++){ ll nxt = n/i; if (nxt != pre){ } } bool ok = false; rep1(j,m+1){ ll k = n/j; mint tmp = mint(n+1)*k*j - mint(j)*j*(k*(k+1)/2); sum += tmp; ll nxt = n / (j+1); if (j >= c){ now = nxt; ok = true; nowi = j+1; break; } } if (ok){ int l = now; rrep(i,l+1){ ll k = now; ll y = nowi; ll nxt = i; ll ny = n/nxt; bool ok2 = false; if (ny >= m){ ny = m; ok2 = true; } mint y1 = (y-1) * y / 2; mint y2 = mint(y) * (2*y-1) * (y - 1) / 6; mint ny1 = (ny+1) * ny / 2; mint ny2 = mint(ny) * (2*ny+1) * (ny + 1) / 6; mint tmp = mint(n+1)*k*(ny1-y1) - mint(k+1)*k/2*(ny2-y2); sum += tmp; nowi = ny+1; now = n / nowi; if (ok2){ break; } } } ans -= sum; outm; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; //cin>>t; rep(i,t){ solve(); } return 0; }