#floor(a^(1/k)) を求める. def Floor_Root(a,k): """floor(a^(1/k)) を求める. a:非負整数 k:正の整数 """ assert 0<=a and 0a: x-=1 return x #================================================== def check(a,b,c,d,x,y): ux=c-a; uy=d-b vx=x-c; vy=y-d return vx*uy-vy*ux>0 #================================================== def solve(): N=10**6 R=10**6 P=[None]*N; k=0 for x in range(-R,R+1): y=Floor_Root(R*R-x*x,2) if k<=1 or check(*P[k-2], *P[k-1], x, y): P[k]=(x,y) k+=1 if k==N: break return P[:k] #================================================== import sys input=sys.stdin.readline write=sys.stdout.write string=lambda p:"{} {}".format(*p) ans=solve() print(len(ans)) write("\n".join(map(string,ans)))