#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;

typedef long long ll;

int main(){
	ll a, b, c;
	cin >> a >> b >> c;
	ll need = a / b + ((a%b) > 0);
	ll need2 = a / c + ((a%c) > 0);
	if (need2 <= need * 2 / 3) cout << "YES" << endl;
	else cout << "NO" << endl;
	return 0;
}