#include using namespace std; typedef signed long long ll; #define _P(...) (void)printf(__VA_ARGS__) #define FOR(x,to) for(x=0;x<(to);x++) #define FORR(x,arr) for(auto& x:arr) #define FORR2(x,y,arr) for(auto& [x,y]:arr) #define ALL(a) (a.begin()),(a.end()) #define ZERO(a) memset(a,0,sizeof(a)) #define MINUS(a) memset(a,0xff,sizeof(a)) template bool chmax(T &a, const T &b) { if(a bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;} //------------------------------------------------------- int N,A,B,C; ll dp[202020][2]; void solve() { int i,j,k,l,r,x,y; string s; cin>>N>>A>>B>>C; FOR(i,N) dp[i][0]=dp[i][1]=1LL<<60; priority_queue> Q; dp[1][1]=A+B; Q.push({-dp[1][1],3}); while(Q.size()) { ll co=-Q.top().first; int cur=Q.top().second/2; int one=Q.top().second%2; Q.pop(); if(dp[cur][one]!=co) continue; // add 1 if(chmin(dp[(cur+1)%N][1],co+A+(one?0:B))) { Q.push({-dp[(cur+1)%N][1],((cur+1)%N)*2+1}); } // mult 2 if(chmin(dp[(cur*2)%N][0],co+C)) { Q.push({-dp[(cur*2)%N][0],((cur*2)%N)*2+0}); } } FOR(i,N) cout<