#include <iostream>
using namespace std;
typedef long long ll;

int main()
{
    ll n, k;
    cin >> n >> k;
    k = n * (n + 1) / 2 - k;
    ll s = 0;
    ll t = n;
    for (ll i = 1; i <= n; i++)
    {
        s += i;
        if ((k - s) % i == 0 && k <= t)
        {
            cout << 1 << endl;
            return 0;
        }
        t += n - i;
    }
    cout << 2 << endl;
}