#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int N,M;
int A[202020],B[202020];
ll dp[303][603];
ll dp2[603];
const ll mo=998244353;

ll dp3[303][303*303*2];

ll comb(int P_,int Q_) {
	static const int N_=1020;
	static ll C_[N_][N_];
	
	if(C_[0][0]==0) {
		int i,j;
		FOR(i,N_) C_[i][0]=C_[i][i]=1;
		for(i=1;i<N_;i++) for(j=1;j<i;j++) C_[i][j]=(C_[i-1][j-1]+C_[i-1][j])%mo;
	}
	if(P_<0 || P_>N_ || Q_<0 || Q_>P_) return 0;
	return C_[P_][Q_];
}

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>M;
	FOR(i,N) cin>>A[i];
	FOR(i,N) cin>>B[i];
	FOR(i,M) {
		FOR(j,601) dp[i][j]=1;
		for(k=i;k<N;k+=M) {
			ZERO(dp2);
			FOR(x,A[k]+1) FOR(y,B[k]+1) (dp2[300+x-y]+=comb(A[k],x)*comb(B[k],y))%=mo;
			FOR(j,601) (dp[i][j]*=dp2[j])%=mo;;
		}
	}
	dp3[0][0]=1;
	FOR(i,M) {
		FOR(j,600*i+1) {
			FOR(x,601) (dp3[i+1][j+x]+=dp[i][x]*dp3[i][j])%=mo;
		}
	}
	cout<<dp3[M][300*M]<<endl;
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}