#include #pragma GCC optimize("Ofast") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; ll ILL=2167167167167167167; const int INF=2100000000; const ll mod=998244353; #define rep(i,a,b) for (ll i=a;i using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a){if(a) cout<<"Yes\n"; else cout<<"No\n";} template void vec_out(vector &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout< T min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} void solve(); // oddloop int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t=1; //cin>>t; rep(i,0,t) solve(); } void solve(){ int N; cin>>N; int ans=N; vector> p(N); rep(i,0,N){ cin>>p[i].first>>p[i].second; } So(p); if(N<=2){ cout<<"1\n"; return; } auto f=[&](pair &a,pair &b,pair &c)->int{ int A=b.second-a.second; int B=a.first-b.first; int C=a.second*b.first-b.second*a.first; return A*c.first+B*c.second+C; }; do{ vector dp(N-1,N); dp[0]=1; rep(i,0,N-2){ chmin(dp[i+1],1+dp[i]); int A=p[i+1].first-p[i].first; int B=p[i+1].second-p[i].second; int C=p[i+2].first-p[i+1].first; int D=p[i+2].second-p[i+1].second; int tmp=__gcd(abs(A),abs(B)); A/=tmp,B/=tmp; tmp=__gcd(abs(C),abs(D)); C/=tmp,D/=tmp; if(A==C&&D==B){ chmin(dp[i+1],dp[i]); continue; } if(i==N-3) continue; int X=f(p[i+1],p[i+2],p[i+3]); int Y=f(p[i+1],p[i+2],p[i]); if(X==0) continue; if((X<0)^(Y<0)) continue; X=f(p[i],p[i+1],p[i+2]); Y=f(p[i],p[i+1],p[i+3]); if(X<0) X*=-1,Y*=-1; if(X