n = gets.to_i
ans = Array.new(n,10000)
a = [[1,1]]
until a.empty?
    x = a.pop
    if ans[x[0] - 1] <= x[1]
        next
    end
    ans[x[0] - 1] = x[1]
    tmp = x[0].to_s(2).count('1')    
    if x[0] + tmp <= n
        a.push([x[0] + tmp, x[1] + 1])
    end
    if x[0] > tmp
        a.push([x[0] - tmp, x[1] + 1])
    end
end

if ans[n - 1] == 10000
    p -1
else
    p ans[n - 1]
end