#include <array>
#include <iostream>
#include <map>

#include <atcoder/modint>

using mint = atcoder::modint998244353;

constexpr int L = 30;
constexpr int N = 4;

int main() {
    std::array<int, N> r, c;
    for (auto&& e : r) std::cin >> e, e -= 4;
    for (auto&& e : c) std::cin >> e, e -= 4;

    using key = std::pair<std::array<int, N>, std::array<int, N>>;
    std::array<std::map<key, mint>, L + 1> dp{};
    dp[0][{ r, c }] = 1;
    for (int i = 0; i < L; ++i) {
        for (const auto& [k, v] : dp[i]) {
            for (int s = 0; s < 1 << ((N - 1) * (N - 1)); ++s) {
                auto [r, c] = k;
                std::array<std::array<int, N>, N> d;
                for (int a = 0; a < N - 1; ++a) {
                    for (int b = 0; b < N - 1; ++b) {
                        int bit = (s >> (a * (N - 1) + b)) & 1;
                        d[a][b] = bit;
                        r[a] -= bit, c[b] -= bit;
                    }
                }
                for (int a = 0; a < N - 1; ++a) {
                    const int b = N - 1;
                    int bit = r[a] & 1;
                    d[a][b] = bit;
                    r[a] -= bit, c[b] -= bit;
                }
                for (int b = 0; b < N - 1; ++b) {
                    const int a = N - 1;
                    int bit = c[b] & 1;
                    d[a][b] = bit;
                    r[a] -= bit, c[b] -= bit;
                }
                {
                    int bit = r[N - 1] & 1;
                    d[N - 1][N - 1] = bit;
                    r[N - 1] -= bit, c[N - 1] -= bit;
                }
                bool ok = (c[N - 1] & 1) == 0;
                for (int a = 0; a < N; ++a) {
                    ok &= r[a] >= 0;
                    r[a] >>= 1;
                }
                for (int b = 0; b < N; ++b) {
                    ok &= c[b] >= 0;
                    c[b] >>= 1;
                }
                if (ok) {
                    dp[i + 1][{ r, c }] += v;
                }
            }
        }
    }

    std::cout << dp[L][key{}].val() << std::endl;

    return 0;
}