import sys,random,bisect
from collections import deque,defaultdict,Counter
from heapq import heapify,heappop,heappush
from itertools import cycle, permutations
from math import log,gcd

input = lambda :sys.stdin.readline().rstrip()
mi = lambda :map(int,input().split())
li = lambda :list(mi())

def cross3(a, b, c):
    return (b[0]-a[0])*(c[1]-a[1]) - (b[1]-a[1])*(c[0]-a[0])

# ps = [(x, y), ...]: ソートされた座標list
def convex_hull(ps):
    qs = []
    N = len(ps)
    for p in ps:
        # 一直線上で高々2点にする場合は ">=" にする
        while len(qs) > 1 and cross3(qs[-1], qs[-2], p) > 0:
            qs.pop()
        qs.append(p)
    t = len(qs)
    for i in range(N-2, -1, -1):
        p = ps[i]
        while len(qs) > t and cross3(qs[-1], qs[-2], p) > 0:
            qs.pop()
        qs.append(p)
    return qs

# O(N)
def inside_convex_polygon0(p0, qs):
    L = len(qs)
    D = [cross3(qs[i-1], p0, qs[i]) for i in range(L)]
    return all(e >= 0 for e in D) or all(e <= 0 for e in D)

# O(log N)
def inside_convex_polygon(p0, qs):
    L = len(qs)
    left = 1; right = L
    q0 = qs[0]
    while left+1 < right:
        mid = (left + right) >> 1
        if cross3(q0, p0, qs[mid]) <= 0:
            left = mid
        else:
            right = mid
    if left == L-1:
        left -= 1
    qi = qs[left]; qj = qs[left+1]
    v0 = cross3(q0, qi, qj)
    v1 = cross3(q0, p0, qj)
    v2 = cross3(q0, qi, p0)
    if v0 < 0:
        v1 = -v1; v2 = -v2
    return 0 <= v1 and 0 <= v2 and v1 + v2 <= v0




def solve_3(N,K,star):

    for p in range(2):
        for x,y in star[p]:
            S = set()
            for xx,yy in star[p^1]:
                xx,yy = xx-x,yy-y
                g = gcd(xx,yy)
                xx,yy = xx//g,yy//g
                if (-xx,-yy) in S:
                    return "Yes"
                S.add((xx,yy))

    return "No"

def solve_4(N,K,star):

    star[0].sort()
    star[1].sort()

    ch = [convex_hull(star[p]) for p in range(2)]
    for p in range(2):
        for x,y in star[p]:
            if inside_convex_polygon((x,y),ch[p^1]):
                return "Yes"
    
    assert False


N,K = mi()
star = [[] for p in range(2)]
for _ in range(N):
    x,y,c = mi()
    star[c-1].append((x,y))

if K == 3:
    print(solve_3(N,K,star))
else:
    print(solve_4(N,K,star))