#include using namespace std; using ll = long long; using ull = unsigned long long; template using pq = priority_queue; template using qp = priority_queue, greater>; #define vec(T, A, ...) vector A(__VA_ARGS__); #define vvec(T, A, h, ...) vector> A(h, vector(__VA_ARGS__)); #define vvvec(T, A, h1, h2, ...) vector>> A(h1, vector>(h2, vector(__VA_ARGS__))); #define endl "\n" #define spa ' ' #define len(A) A.size() #define all(A) begin(A), end(A) #define fori1(a) for(ll _ = 0; _ < (a); _++) #define fori2(i, a) for(ll i = 0; i < (a); i++) #define fori3(i, a, b) for(ll i = (a); i < (b); i++) #define fori4(i, a, b, c) for(ll i = (a); ((c) > 0 || i > (b)) && ((c) < 0 || i < (b)); i += (c)) #define overload4(a, b, c, d, e, ...) e #define fori(...) overload4(__VA_ARGS__, fori4, fori3, fori2, fori1)(__VA_ARGS__) const ll MOD1 = 1000000007; const ll MOD9 = 998244353; template auto min(const T& a){ return *min_element(all(a)); } template auto max(const T& a){ return *max_element(all(a)); } template inline bool chmax(T &a, const S &b) { return (a < b ? a = b, 1 : 0); } template inline bool chmin(T &a, const S &b) { return (a > b ? a = b, 1 : 0); } void print(){cout << '\n';} template void print(Head &&head, Tail &&... tail) { cout << head; if (sizeof...(Tail)) cout << ' '; print(forward(tail)...); } template void print(vector &A){ int n = A.size(); for(int i = 0; i < n; i++){ cout << A[i]; if(i == n - 1) cout << '\n'; else cout << ' '; } } template void print(vector> &A){ for(auto &row: A) print(row); } template void prisep(vector &A, S sep){ int n = A.size(); for(int i = 0; i < n; i++){ cout << A[i]; if(i == n - 1) cout << '\n'; else cout << sep; } } template void priend(T A, S end){ cout << A << end; } template void priend(T A){ priend(A, ' '); } template void inp(T&... a){ (cin >> ... >> a); } template void inp(vector &A){ for(auto &a:A) cin >> a; } template void inp(vector> &A){ for(auto &row:A) input(row); } template T sum(vector &A){ T tot = 0; for(auto a:A) tot += a; return tot; } void solve(){ ll n; inp(n); ll ans = 0; ll k = (n + 2) / 3; ans += 3 * k * (k + 1) / 2 - 2 * k; k = (n + 1) / 3; ans += 9 * k * (k + 1) * (2 * k + 1) / 6 - 6 * k * (k + 1) / 2 + k; k = n / 3; ans += 27 * k * k * (k + 1) * (k + 1) / 4; print(ans); } int main(){ cin.tie(0)->sync_with_stdio(0); int t; t = 1; // cin >> t; while(t--) solve(); return 0; }