#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int N;
ll X[805],Y[805],T[805];
long double D[808][808];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N;
	FOR(i,N) cin>>X[i]>>Y[i]>>T[i];
	FOR(y,N) FOR(x,y) {
		if(T[x]==T[y]) {
			D[y][x]=hypot((X[x]-X[y]),(Y[x]-Y[y]));
		}
		else {
			D[y][x]=abs(hypot(X[x],Y[x])-hypot(X[y],Y[y]));
		}
		D[x][y]=D[y][x];
	}
	FOR(k,N) FOR(x,N) FOR(y,N) D[x][y]=min(D[x][y],max(D[x][k],D[k][y]));
	cout<<(ll)ceil(D[0][N-1]*D[0][N-1])<<endl;
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}