#include #pragma GCC optimize("Ofast") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; ll ILL=2167167167167167167; const int INF=2100000000; const int mod=998244353; #define rep(i,a,b) for (ll i=a;i using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a){if(a) cout<<"Yes\n"; else cout<<"No\n";} template void vec_out(vector &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout< T min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} // return val=p(N) // a=p[0].first^p[0].second * ... *p[N-1].first^p[N-1].second // for all i: p[i].first is prime number // O(sqrt(val)) std::vector> Prime_factorization(long long val){ assert(val>=1); if(val==1){ return {}; } int ind=0; std::vector> ans; for(long long i=2;i*i<=val;i++){ if(val%i!=0) continue; ans.push_back({i,0}); while(val%i==0){ ans[ind].second++; val/=i; } ind++; } if(val!=1) ans.push_back({val,1}); return ans; } void solve(); // oddloop int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t=1; //cin>>t; rep(i,0,t) solve(); } void solve(){ ll B,N; //cin>>B>>N; string S; cin>>S; N=0; rep(i,0,12) N*=10ll,N+=(ll)(S[i]-'0'); B=1e12; auto p=Prime_factorization(B); bool ans=1; auto f=[&](ll p,ll e)->void{ ll M=1; rep(i,0,e) M*=p; ll X=N%M; if(X==0) return; ll D=0; while(X%p==0) D++,X/=p; if(D&1){ ans=0; return; } if(p==2){ if(e==1) return; if(X%4>=2) ans=0; return; } rep(i,0,p){ if((i*i)%p==X%p) break; if(i+1==p) ans=0; } }; for(auto x:p) f(x.first,x.second); cout<<(ans ? "YES\n" : "NO\n"); }