#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (n); i++)
#define per(i, n) for (int i = (n)-1; i >= 0; i--)
#define rep2(i, l, r) for (int i = (l); i < (r); i++)
#define per2(i, l, r) for (int i = (r)-1; i >= (l); i--)
#define each(e, v) for (auto &e : v)
#define MM << " " <<
#define pb push_back
#define eb emplace_back
#define all(x) begin(x), end(x)
#define rall(x) rbegin(x), rend(x)
#define sz(x) (int)x.size()
using ll = long long;
using pii = pair<int, int>;
using pil = pair<int, ll>;
using pli = pair<ll, int>;
using pll = pair<ll, ll>;

template <typename T>
using minheap = priority_queue<T, vector<T>, greater<T>>;

template <typename T>
using maxheap = priority_queue<T>;

template <typename T>
bool chmax(T &x, const T &y) {
    return (x < y) ? (x = y, true) : false;
}

template <typename T>
bool chmin(T &x, const T &y) {
    return (x > y) ? (x = y, true) : false;
}

template <typename T>
int flg(T x, int i) {
    return (x >> i) & 1;
}

template <typename T>
void print(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << (i == n - 1 ? '\n' : ' ');
    if (v.empty()) cout << '\n';
}

template <typename T>
void printn(const vector<T> &v, T x = 0) {
    int n = v.size();
    for (int i = 0; i < n; i++) cout << v[i] + x << '\n';
}

template <typename T>
int lb(const vector<T> &v, T x) {
    return lower_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
int ub(const vector<T> &v, T x) {
    return upper_bound(begin(v), end(v), x) - begin(v);
}

template <typename T>
void rearrange(vector<T> &v) {
    sort(begin(v), end(v));
    v.erase(unique(begin(v), end(v)), end(v));
}

template <typename T>
vector<int> id_sort(const vector<T> &v, bool greater = false) {
    int n = v.size();
    vector<int> ret(n);
    iota(begin(ret), end(ret), 0);
    sort(begin(ret), end(ret), [&](int i, int j) { return greater ? v[i] > v[j] : v[i] < v[j]; });
    return ret;
}

template <typename S, typename T>
pair<S, T> operator+(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first + q.first, p.second + q.second);
}

template <typename S, typename T>
pair<S, T> operator-(const pair<S, T> &p, const pair<S, T> &q) {
    return make_pair(p.first - q.first, p.second - q.second);
}

template <typename S, typename T>
istream &operator>>(istream &is, pair<S, T> &p) {
    S a;
    T b;
    is >> a >> b;
    p = make_pair(a, b);
    return is;
}

template <typename S, typename T>
ostream &operator<<(ostream &os, const pair<S, T> &p) {
    return os << p.first << ' ' << p.second;
}

struct io_setup {
    io_setup() {
        ios_base::sync_with_stdio(false);
        cin.tie(NULL);
        cout << fixed << setprecision(15);
    }
} io_setup;

const int inf = (1 << 30) - 1;
const ll INF = (1LL << 60) - 1;
// const int MOD = 1000000007;
const int MOD = 998244353;

template <typename T>
T kth_root_integer(T a, int k) {
    if (k == 1) return a;
    auto check = [&](T x) {
        T mul = 1;
        for (int j = 0; j < k; j++) {
            if (__builtin_mul_overflow(mul, x, &mul)) return false;
        }
        return mul <= a;
    };
    int n = 4 * sizeof(T);
    T ret = 0;
    for (int i = n - 1; i >= 0; i--) {
        if (check(ret | (T(1) << i))) ret |= T(1) << i;
    }
    return ret;
}

int main() {
    int A;
    cin >> A;

    int M = 333;
    int N = 111;

    A %= M;

    vector<ll> pw3(N + 1, 1);
    rep(i, N + 1) pw3[i] = 1LL * i * i * i;

    int L = 4444;
    vector<ll> pw4(L + 1, 1);
    rep(i, L + 1) pw4[i] = 1LL * i * i * i * i;

    ll ma = pw4[L];

    ll ans = 0;

    auto dfs = [&](int i, vector<ll> v, ll S, auto &&dfs) -> ll {
        if (i == 2) {
            int t = ub(pw4, S) - 1;
            if (t < v[2]) return 0;
            return (t - v[2]) / N + 1;
        }
        ll ret = 0;
        for (ll p = v[i];; p += N) {
            ll NS = S - pw4[p];
            if (NS < 0) break;
            ret += dfs(i + 1, v, NS, dfs);
        }
        return ret;
    };

    rep2(x, 1, N + 1) rep2(y, 1, N + 1) rep2(z, 1, N + 1) {
        int r = z + N * ((L - z) / N);
        int c = (L - z) / N + 1;
        ll t = pw3[x] + pw3[y] + pw3[z];
        if (t % M == A) {
            for (ll i = x; i <= L && pw4[i] <= ma; i += N) {
                for (ll j = y; j <= L && pw4[i] + pw4[j] <= ma; j += N) {
                    // ll S = ma - pw4[i] - pw4[j];
                    int s = r, cnt = c;
                    while (pw4[s] > ma - pw4[i] - pw4[j]) cnt--, s -= N;
                    ans += cnt;
                }
            }
        }
    }

    cout << ans << '\n';
}