#include //#include using namespace std; //using namespace atcoder; //using mint = modint1000000007; //const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; //const int INF = 1e9; //const long long LINF = 1e18; #define rep(i, n) for (long long i = 0; i < (n); ++i) #define rep2(i,l,r)for(long long i=(l);i<(r);++i) #define rrep(i, n) for (long long i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(long long i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define endl "\n" #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int a; cin >> a; long long lim = 4444LL * 4444 * 4444 * 4444; vectorv4(4445, 1); rep(i, v4.size()) rep(j, 4)v4[i] *= i; vector>v3(333, vector(4446)); rep2(i, 1, 4445) v3[(i * i * i) % 333][i]++; rep(i, 333)rep(j, 4445) v3[i][j + 1] += v3[i][j]; long long ans = 0; rep2(i, 1, 4445) { int k = 4444;//ok max rep2(j, 1, i + 1) { if (v4[i] + v4[j] > lim)break; long long y = (333 - (i * i * i - j * j * j) % 333 + a) % 333; while (v4[i] + v4[j] + v4[k] > lim) { k--; if (0 == k)break; } if (0 == k)break; if (i != j)ans += v3[y][k] * 2; else ans += v3[y][k]; } } cout << ans << endl; return 0; }