#include using namespace std; /////////////////////////////////////////////////// /// Variables /// /////////////////////////////////////////////////// #define ll long long #define REP(x,n) for(int x=0;x void showendl(T &x){cout< void show(pair &x){cout<<"("< void showendl(pair &x){cout<<"("< void debug(H&& h){showendl(h);} template void debug(H&& h, Ts&&... ts){show(h);debug(forward(ts)...);} template void debug(vector &vt){int i=0;int size = vt.size();for(auto x: vt)++i!=size ? show(x) : showendl(x);} template void debug(vector> &vt){int i=0;int size = vt.size();for(int k=0; k void debug(deque &vt){int i=0;int size = vt.size();for(auto x: vt)++i!=size ? show(x) : showendl(x);} template void debug(stack s){int i=0;int size = s.size();while(!s.empty()){T w = s.top();++i!=size ? show(w) : showendl(w);s.pop();}} template void debug(queue s){int i=0;int size = s.size();while(!s.empty()){T w = s.front();++i!=size ? show(w) : showendl(w);s.pop();}} template void debug(priority_queue s){int i=0;int size = s.size();while(!s.empty()){T w = s.top();++i!=size ? show(w) : showendl(w);s.pop();}} } /////////////////////////////////////////////////// /// Function / Library /// /////////////////////////////////////////////////// // a^b // O(logb) ll intpow(ll a,ll b){ ll ans = 1; while(b){if(b & 1) {ans *= a;} a *= a; b /= 2;}return ans;} // a^b mod p // O(logb) ll modpow(ll a, ll b, ll p){ll ans = 1; while(b){if(b & 1) {(ans *= a) %= p;} (a *= a) %= p; b /= 2;}return ans;} // 負の数にも対応した % 演算 ll mod(ll val, ll m) {ll res = val % m; if (res < 0) res += m; return res;} // mod. m での a の逆元 a^{-1} を計算する 逆元の存在条件: gcd(a, m) = 1 ll modinv(ll a, ll m) {ll b = m, u = 1, v = 0; while (b) {ll t = a / b; a -= t * b; swap(a, b); u -= t * v; swap(u, v);} u %= m; if (u < 0) u += m; return u;} template inline bool chmin(T& a, T b) {if (a > b) {a = b;return true;}return false;} template inline bool chmax(T& a, T b) {if (a < b) {a = b;return true;}return false;} // 整数を桁ごとにvectorへ // O(桁数) template vector num_digit (T a){string ss = to_string(a);int size = ss.size();vector v(size);for(int i=0; i ll int digit_length(T a){string ss = to_string(a);return (ll int)ss.size();} // gcd(最大公約数) // O(log(min(a,b))) ll int gcd(ll int a, ll int b){if (a%b == 0){return(b);}else{return(gcd(b, a%b));}} // lcm(最小公倍数)// O(log(min(a,b))) ll int lcm(ll int a, ll int b){return a / gcd(a, b) * b;} ///////////////////////////////////////////////////////////// int cal_hash(int x){ while(1){ vector num = num_digit(x); x = 0; REP(i, (int)num.size()){ x += num[i]; } if(x < 10){ return x; } } } int main (){ // ifstream in("input.txt"); // cin.rdbuf(in.rdbuf()); // エラストテネス int n = 200010; bitset<1000000> is_prime(0); // 十分大きなサイズを確保します for (int i = 2; i <= n; ++i) is_prime.set(i); // とりあえず全部ふるいに入れます for (int i = 2; i <= n; ++i) { if (is_prime[i]) { // 素数 i を発見したら for (int j = i * 2; j <= n; j += i) { is_prime.reset(j); // i の倍数をふるい落とす } } } int K, N; cin >> K >> N; vector pri; REP2(i, K, N+1){ if(is_prime[i]) pri.push_back(i); } int ans = 0; int smax = 0; int ps = pri.size(); REP(i,ps){ int jm = min(i+10, ps); int s = 0; vector cnt(10, 0); REP2(j,i,jm){ int h = cal_hash(pri[j]); if(!cnt[h]){ cnt[h] = 1; s++; }else{ break; } } if(smax <= s){ smax = max(smax, s); ans = pri[i]; } } cout << ans << endl; }