#include #pragma GCC optimize("Ofast") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; ll ILL=2167167167167167167; const int INF=2100000000; const int mod=998244353; #define rep(i,a,b) for (ll i=a;i using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a){if(a) cout<<"Yes\n"; else cout<<"No\n";} template void vec_out(vector &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout< T min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} std::vector> tree_in(int N){ std::vector> G(N); for(int i=0;i>a>>b; a--,b--; G[a].push_back(b); G[b].push_back(a); } return G; } std::tuple,std::vector,std::vector> tree_order_pare_depth(std::vector> &G,int root){ int n=G.size(); std::vector order={root},pare(n,-1),depth(n); pare[root]=-2; for(int i=0;i tree_diameter_path(std::vector> &G){ int n=G.size(); auto r=(std::get<0>(tree_order_pare_depth(G,0))).at(n-1); std::vector order,pare,depth,ans; tie(order,pare,depth)=tree_order_pare_depth(G,r); int ind=order[n-1]; while(ind!=-2){ ans.push_back(ind); ind=pare[ind]; } return ans; } void solve(); // oddloop int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t=1; //cin>>t; rep(i,0,t) solve(); } void solve(){ int N; cin>>N; auto G=tree_in(N); vector pare,order,dep; tie(order,pare,dep)=tree_order_pare_depth(G,0); vector p(N); rep(i,0,N){ cin>>p[i]; } int ans=0; for(int i=N-1;i>0;i--){ int a=order[i]; if(p[a]==0){ p[pare[a]]^=1; ans++; } } cout<<(p[0] ? ans : -1)<<"\n"; }