#define MOD_TYPE 2 #include using namespace std; #include // #include // #include // #include using namespace atcoder; #if 0 #include #include using Int = boost::multiprecision::cpp_int; using lld = boost::multiprecision::cpp_dec_float_100; #endif #if 0 #include #include #include #include using namespace __gnu_pbds; using namespace __gnu_cxx; template using extset = tree, rb_tree_tag, tree_order_statistics_node_update>; #endif #if 1 #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #endif #pragma region Macros using ll = long long int; using ld = long double; using pii = pair; using pll = pair; using pld = pair; template using smaller_queue = priority_queue, greater>; #if MOD_TYPE == 1 constexpr ll MOD = ll(1e9 + 7); #else #if MOD_TYPE == 2 constexpr ll MOD = 998244353; #else constexpr ll MOD = 1000003; #endif #endif using mint = static_modint; constexpr int INF = (int)1e9 + 10; constexpr ll LINF = (ll)4e18; const double PI = acos(-1.0); constexpr ld EPS = 1e-10; constexpr int Dx[] = {0, 0, -1, 1, -1, 1, -1, 1, 0}; constexpr int Dy[] = {1, -1, 0, 0, -1, -1, 1, 1, 0}; #define REP(i, m, n) for (ll i = m; i < (ll)(n); ++i) #define rep(i, n) REP(i, 0, n) #define REPI(i, m, n) for (int i = m; i < (int)(n); ++i) #define repi(i, n) REPI(i, 0, n) #define YES(n) cout << ((n) ? "YES" : "NO") << "\n" #define Yes(n) cout << ((n) ? "Yes" : "No") << "\n" #define all(v) v.begin(), v.end() #define NP(v) next_permutation(all(v)) #define dbg(x) cerr << #x << ":" << x << "\n"; #define UNIQUE(v) v.erase(unique(all(v)), v.end()) struct io_init { io_init() { cin.tie(nullptr); ios::sync_with_stdio(false); cout << setprecision(30) << setiosflags(ios::fixed); }; } io_init; template inline bool chmin(T &a, T b) { if (a > b) { a = b; return true; } return false; } template inline bool chmax(T &a, T b) { if (a < b) { a = b; return true; } return false; } inline ll floor(ll a, ll b) { if (b < 0) a *= -1, b *= -1; if (a >= 0) return a / b; return -((-a + b - 1) / b); } inline ll ceil(ll a, ll b) { return floor(a + b - 1, b); } template inline void Fill(A (&array)[N], const T &val) { fill((T *)array, (T *)(array + N), val); } template vector compress(vector &v) { vector val = v; sort(all(val)), val.erase(unique(all(val)), val.end()); for (auto &&vi : v) vi = lower_bound(all(val), vi) - val.begin(); return val; } template constexpr istream &operator>>(istream &is, pair &p) noexcept { is >> p.first >> p.second; return is; } template constexpr ostream &operator<<(ostream &os, pair p) noexcept { os << p.first << " " << p.second; return os; } ostream &operator<<(ostream &os, mint m) { os << m.val(); return os; } ostream &operator<<(ostream &os, modint m) { os << m.val(); return os; } template constexpr istream &operator>>(istream &is, vector &v) noexcept { for (int i = 0; i < v.size(); i++) is >> v[i]; return is; } template constexpr ostream &operator<<(ostream &os, vector &v) noexcept { for (int i = 0; i < v.size(); i++) os << v[i] << (i + 1 == v.size() ? "" : " "); return os; } template constexpr void operator--(vector &v, int) noexcept { for (int i = 0; i < v.size(); i++) v[i]--; } random_device seed_gen; mt19937_64 engine(seed_gen()); inline ll randInt(ll l, ll r) { return engine() % (r - l + 1) + l; } struct BiCoef { vector fact_, inv_, finv_; BiCoef(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) { fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1); for (int i = 2; i < n; i++) { fact_[i] = fact_[i - 1] * i; inv_[i] = -inv_[MOD % i] * (MOD / i); finv_[i] = finv_[i - 1] * inv_[i]; } } mint C(ll n, ll k) const noexcept { if (n < k || n < 0 || k < 0) return 0; return fact_[n] * finv_[k] * finv_[n - k]; } mint P(ll n, ll k) const noexcept { return C(n, k) * fact_[k]; } mint H(ll n, ll k) const noexcept { return C(n + k - 1, k); } mint Ch1(ll n, ll k) const noexcept { if (n < 0 || k < 0) return 0; mint res = 0; for (int i = 0; i < n; i++) res += C(n, i) * mint(n - i).pow(k) * (i & 1 ? -1 : 1); return res; } mint fact(ll n) const noexcept { if (n < 0) return 0; return fact_[n]; } mint inv(ll n) const noexcept { if (n < 0) return 0; return inv_[n]; } mint finv(ll n) const noexcept { if (n < 0) return 0; return finv_[n]; } }; BiCoef bc(300010); #pragma endregion // ------------------------------- using M1 = modint1000000007; using M2 = modint998244353; using hash_t = pair; namespace atcoder { bool operator<(const M1 &t1, const M1 &t2) { return t1.val() < t2.val(); } bool operator<(const M2 &t1, const M2 &t2) { return t1.val() < t2.val(); } } // namespace atcoder template struct Hash { int n; T s; static long long B; bool calc_rev; vector sum1, sum1_rev; vector sum2, sum2_rev; vector Bp1; vector Bp2; Hash() {} Hash(T &s, bool calc_rev = true) : s(s), n(s.size()), calc_rev(calc_rev), Bp1(n + 1), Bp2(n + 1) { Bp1[0] = 1, Bp2[0] = 1; for (int i = 0; i < n; i++) { Bp1[i + 1] = Bp1[i] * B, Bp2[i + 1] = Bp2[i] * B; } sum1.assign(n + 1, 0), sum2.assign(n + 1, 0); for (int i = n - 1; i >= 0; i--) { sum1[i] = sum1[i + 1] * B + s[i]; sum2[i] = sum2[i + 1] * B + s[i]; } if (not calc_rev) return; sum1_rev.assign(n + 1, 0), sum2_rev.assign(n + 1, 0); for (int i = 0; i < n; i++) { sum1_rev[i + 1] = sum1_rev[i] * B + s[i]; sum2_rev[i + 1] = sum2_rev[i] * B + s[i]; } } hash_t query(int l, int r, bool rev = false) { assert(l <= r); if (rev) { assert(calc_rev); hash_t res = {sum1_rev[r] - sum1_rev[l] * Bp1[r - l], sum2_rev[r] - sum2_rev[l] * Bp2[r - l]}; return res; } hash_t res = {sum1[l] - sum1[r] * Bp1[r - l], sum2[l] - sum2[r] * Bp2[r - l]}; return res; } bool is_palindrome(int l, int r) { assert(calc_rev); return query(l, (l + r) / 2, false) == query((l + r + 1) / 2, r, true); } hash_t calc_hash(T &t) { M1 t1 = 0; M2 t2 = 0; for (int i = int(t.size()) - 1; i >= 0; i--) { t1 = t1 * B + t[i]; t2 = t2 * B + t[i]; } return {t1, t2}; } }; random_device B_seed; mt19937 B_engine(B_seed()); template long long Hash::B = (long long)(B_engine()) + 500010; void solve() { string s; cin >> s; int n = s.size(); vector dp(n + 1, -INF); dp[0] = INF; Hash hash(s); repi(i, n) { REPI(j, i + 1, n + 1) { if (not hash.is_palindrome(i, j)) continue; chmax(dp[j], min(dp[i], j - i)); } } cout << dp[n] << "\n"; } int main() { solve(); }