S=input() n=len(S) DP=[1 for _ in range(n+1)] DP[0]=len(S) s_to_n={chr(i+97):i for i in range(26)} def is_kaibun(s): n=len(s) for i in range(n//2): if s[i]!=s[n-1-i]: return 0 return 1 for i in range(n): cnt=1<