#include <bits/stdc++.h>
using namespace std;
using ll = long long;

struct problem_H {
    int MAX_LOGV, N;
    vector<vector<pair<int, int>>> G;
    vector<vector<int>> parent;
    vector<ll> dp;
    vector<int> depth;
    vector<int> parent_or_size;
    vector<tuple<ll, int, int>> diameter;
    queue<int> que;

    problem_H(int n) : N(n) {
        MAX_LOGV = __lg(N) + 1;
        G.resize(N);
        parent.resize(MAX_LOGV, vector<int>(N, -1));
        parent_or_size.resize(N, -1);
        dp.resize(N), depth.resize(N);
        diameter.resize(N);
        for(int i = 0; i < N; i++) diameter[i] = make_tuple(0, i, i);
    }

    int leader(int v){ return parent_or_size[v] < 0 ? v : parent_or_size[v]; }

    void merge(int u, int v, int w){
        int x = leader(u), y = leader(v);
        if(-parent_or_size[x] < -parent_or_size[y]) {
            swap(x, y);
            swap(u, v);
        }
        parent_or_size[x] += parent_or_size[y];

        int log_limit = __lg(-parent_or_size[x]) + 1;

        G[u].emplace_back(v, w);
        G[v].emplace_back(u, w);
        parent[0][v] = u;
        depth[v] = depth[u] + 1;
        dp[v] = dp[u] + w;

        que.emplace(v);

        while(!que.empty()){
            v = que.front();
            que.pop();
            parent_or_size[v] = x;
            for(int i = 0; i + 1 < log_limit; i++){
                if(parent[i][v] == -1) parent[i + 1][v] = -1;
                else parent[i + 1][v] = parent[i][parent[i][v]];
            }
            for(auto &edge : G[v]){
                tie(u, w) = edge;
                if(parent[0][v] == u) continue;
                que.emplace(u);
                parent[0][u] = v;
                depth[u] = depth[v] + 1;
                dp[u] = dp[v] + w;
            }
        }

        update_diameter(x, y);
    }

    void update_diameter(int x, int y){
        tuple<ll, int, int> mx = max(diameter[x], diameter[y]);
        array<int, 4> cv;
        ll temp;
        tie(temp, cv[0], cv[1]) = diameter[x];
        tie(temp, cv[2], cv[3]) = diameter[y];
        for(int i = 0; i < 2; i++){
            for(int j = 2; j < 4; j++){
                mx = max(mx, make_tuple(dist(cv[i], cv[j]), cv[i], cv[j]));
            }
        }
        diameter[x] = mx;
    }

    long long dist(int u, int v){
        if(leader(u) != leader(v)) return -1;
        if(depth[v] < depth[u]) swap(v, u);
        long long res = dp[u] + dp[v];
        int d = depth[v] - depth[u];
        for(int i = MAX_LOGV - 1; i >= 0; i--){
            if(d >> i & 1) v = parent[i][v];
        }
        if(u == v) return res - 2 * dp[v];
        for(int i = MAX_LOGV - 1; i >= 0; i--){
            if(parent[i][v] != parent[i][u]){
                v = parent[i][v];
                u = parent[i][u];
            }
        }
        v = parent[0][v];
        return res - 2 * dp[v];
    }
};

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);

    int N, Q;
    ll X;
    cin >> N >> X >> Q;

    problem_H uf(N);
    
    int type, u, v, w;
    while(Q--){
        cin >> type;
        if(type == 1){
            cin >> v >> w;
            uf.merge(v, X, w);
        }else if(type == 2){
            cin >> u >> v;
            ll d = uf.dist(u, v);
            cout << d << '\n';
            if(d != -1) (X += d) %= N;
        }else if(type == 3){
            cin >> v;
            cout << get<0>(uf.diameter[uf.leader(v)]) << '\n';
        }else{
            cin >> v;
            X += v;
            if(X >= N) X -= N;
        }
    }
}