#pragma GCC target("avx") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include using namespace std; #define rep(i,n) for(int i = 0; i < (int)n; i++) #define FOR(n) for(int i = 0; i < (int)n; i++) #define repi(i,a,b) for(int i = (int)a; i < (int)b; i++) #define pb push_back #define all(x) x.begin(),x.end() //#define mp make_pair #define vi vector #define vvi vector #define vll vector #define vvll vector #define vs vector #define vvs vector #define vc vector #define vvc vector #define pii pair #define pllll pair #define vpii vector> #define vpllll vector> #define vpis vector> #define vplls vector> #define vpsi vector> #define vpsll vector> template void chmax(T &a, const T &b) {a = (a > b? a : b);} template void chmin(T &a, const T &b) {a = (a < b? a : b);} using ll = long long; using ld = long double; using ull = unsigned long long; const ll INF = numeric_limits::max() / 2; const ld pi = 3.1415926535897932384626433832795028; const ll mod = 998244353; int dx[] = {-1, 0, 1, 0, -1, -1, 1, 1}; int dy[] = {0, -1, 0, 1, -1, 1, -1, 1}; #define int long long void solve() { int n; cin >> n; vi l(n), r(n), a(n); FOR(n) cin >> l[i] >> r[i] >> a[i]; int q; cin >> q; vi x(q); FOR(q) cin >> x[i]; vector> query; FOR(n) { query.push_back({0, l[i], a[i]}); query.push_back({1, r[i]+1, a[i]}); } FOR(q) { query.push_back({2, x[i], i}); } vector order(2*n+q); iota(all(order), 0); sort(all(order), [&](int i, int j) { if(query[i][1] != query[j][1]) return query[i][1] < query[j][1]; return query[i][0] < query[j][0]; }); multiset st; int mex = 0; vi ans(q, -1); for(int i : order) { auto e = query[i]; if(e[0] == 0) { st.insert(e[2]); while(st.find(mex) != st.end()) { mex++; } }else if(e[0] == 1) { st.erase(st.find(e[2])); if(st.find(e[2]) == st.end()) chmin(mex, e[2]); }else { ans[e[2]] = mex; } } for(auto e : ans) cout << e << endl; } signed main() { cin.tie(nullptr); ios::sync_with_stdio(false); solve(); return 0; }