// #include <bits/stdc++.h>
#include <string.h>

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <ciso646>
#include <climits>
#include <cmath>
#include <complex>
#include <cstdio>
#include <functional>
#include <iomanip>
#include <iostream>
#include <map>
#include <numeric>
#include <queue>
#include <random>
#include <set>
#include <stack>
#include <string>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

#define For(i, a, b) for (int i = (int)(a); (i) < (int)(b); ++(i))
#define rFor(i, a, b) for (int i = (int)(a)-1; (i) >= (int)(b); --(i))
#define rep(i, n) For(i, 0, n)
#define rrep(i, n) rFor(i, n, 0)
#define fi first
#define se second

#include <atcoder/modint>

#include <algorithm>
#include <cassert>
#include <vector>

namespace rklib {

template <class T>
bool chmax(T &a, const T &b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

template <class T>
bool chmin(T &a, const T &b) {
    if (a > b) {
        a = b;
        return true;
    }
    return false;
}

template <class T>
bool chmin_non_negative(T &a, const T &b) {
    if (a < 0 || a > b) {
        a = b;
        return true;
    }
    return false;
}

template <class T>
T div_floor(T a, T b) {
    if (b < 0) a *= -1, b *= -1;
    return a >= 0 ? a / b : (a + 1) / b - 1;
}

template <class T>
T div_ceil(T a, T b) {
    if (b < 0) a *= -1, b *= -1;
    return a > 0 ? (a - 1) / b + 1 : a / b;
}

}  // namespace rklib


using namespace std;
using namespace rklib;

using lint = long long;
using pii = pair<int, int>;
using pll = pair<lint, lint>;

using mint = atcoder::modint;

int main() {
    string s;
    cin >> s;

    int n = s.size();
    mint sum[n + 1];
    rep(i, n) {
        if (s[i] == '0') {
            sum[i + 1] = 1;
        } else if (s[i] == '?') {
            sum[i + 1] = mint(2).inv();
        }
        sum[i + 1] += sum[i];
    }

    mint ans = 0;
    rep(i, n) {
        if (s[i] == '1') {
            ans += sum[i] * (sum[n] - sum[i + 1]);
        } else if (s[i] == '?') {
            ans += sum[i] * (sum[n] - sum[i + 1]) * mint(2).inv();
        }
    }
    ans *= mint(2).pow(count(s.begin(), s.end(), '?'));
    printf("%u\n", ans.val());
}