# S head, S tailを用意し、それぞれTと何個違うかdiffを数える
# headで合うためにはdiffは偶数必要、tailで合うためにはdiffは奇数必要
# 偶数のhead diff, 奇数のtail diffで小さいほうが答え
# 両方ない場合もあるのだろうか。。。

N = int(input())
S_head = input()
S_tail = S_head[::-1]
T = input()

S_head_diff = 0
for i in range(N):
    if S_head[i] != T[i]:
        S_head_diff += 1

S_tail_diff = 0
for i in range(N):
    if S_tail[i] != T[i]:
        S_tail_diff += 1

ans_list = []
if S_head_diff %2 == 0:
    ans_list.append(S_head_diff)
if S_tail_diff %2 == 1:
    ans_list.append(S_tail_diff)
ans = min(ans_list)
print(ans)