#include <bits/stdc++.h>
using namespace std;
using ll = long long;

int main(){
    ios::sync_with_stdio(false);
    cin.tie(0);
    ll A, B;
    cin >> A >> B;
    A--;
    string a = to_string(A), b = to_string(B);

    auto f = [&](string s){
        int n = s.size();
        ll dp[n + 1][2][10] = {}, dp2[n + 1][2][10] = {}, dp3[n + 1][2][2] = {};
        dp[0][1][0] = 1;
        for(int i = 0; i < n; i++){
            for(int j = 0; j < 2; j++){
                int r = j ? s[i] - '0' : 9;
                for(int k = 0; k < 10; k++){
                    if(dp[i][j][k] == 0) continue;
                    for(int l = 0; l <= r; l++){
                        if(k == 1 && l == 2){
                            dp[i + 1][j & (l == r)][l] += dp[i][j][k];
                            dp2[i + 1][j & (l == r)][l] += dp2[i][j][k] + dp[i][j][k];
                        }else{
                            dp[i + 1][j & (l == r)][l] += dp[i][j][k];
                            dp2[i + 1][j & (l == r)][l] += dp2[i][j][k];
                        }
                    }
                }
            }
        }
        //桁,値がギリギリか,leading_zero
        dp3[0][1][1] = 1;
        for(int i = 0; i < n; i++){
            for(int j = 0; j < 2; j++){
                int r = j ? s[i] - '0' : 9;
                if(i == n - 1){
                    for(int k = 2; k <= r && k <= 2; k++){
                        dp3[i + 1][j & (k == r)][0] += dp3[i][j][0];
                        dp3[i + 1][j & (k == r)][0] += dp3[i][j][1];
                    }
                }else{
                    for(int k = 0; k <= r; k++){
                        dp3[i + 1][j & (k == r)][0] += dp3[i][j][0];
                        if(k == 0){
                            dp3[i + 1][j & (k == r)][1] += dp3[i][j][1];
                        }else if(k == 2){
                            dp3[i + 1][j & (k == r)][0] += dp3[i][j][1];
                        }
                    }
                }
            }
        }
        ll ans = dp3[n][0][0] + dp3[n][1][0];
        for(int i = 0; i < 2; i++){
            for(int j = 0; j < 10; j++){
                ans += dp2[n][i][j];
            }
        }
        return ans;
    };
    cout << f(b) - f(a) - (a == "1" || (a[0] == '2' && a.back() == '1')) << '\n';
}