#include using namespace std; #define FOR(i,m,n) for(int i=(m);i<(n);++i) #define REP(i,n) FOR(i,0,n) #define ALL(v) (v).begin(),(v).end() using ll = long long; constexpr int INF = 0x3f3f3f3f; constexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL; constexpr double EPS = 1e-8; constexpr int MOD = 998244353; // constexpr int MOD = 1000000007; constexpr int DY4[]{1, 0, -1, 0}, DX4[]{0, -1, 0, 1}; constexpr int DY8[]{1, 1, 0, -1, -1, -1, 0, 1}; constexpr int DX8[]{0, -1, -1, -1, 0, 1, 1, 1}; template inline bool chmax(T& a, U b) { return a < b ? (a = b, true) : false; } template inline bool chmin(T& a, U b) { return a > b ? (a = b, true) : false; } struct IOSetup { IOSetup() { std::cin.tie(nullptr); std::ios_base::sync_with_stdio(false); std::cout << fixed << setprecision(20); } } iosetup; int main() { int n; cin >> n; vector h(n), t(n); REP(i, n) cin >> h[i]; REP(i, n) cin >> t[i]; int q; cin >> q; vector a(q), b(q); REP(i, q) cin >> a[i] >> b[i], --a[i], --b[i]; vector v(n * 2); ranges::copy(h, v.begin()); ranges::copy(t, next(v.begin(), n)); ranges::sort(v); v.erase(unique(ALL(v)), v.end()); REP(i, n) h[i] = distance(v.begin(), ranges::lower_bound(v, h[i])); REP(i, n) t[i] = distance(v.begin(), ranges::lower_bound(v, t[i])); // REP(i, n) cout << h[i] << " \n"[i + 1 == n]; // REP(i, n) cout << t[i] << " \n"[i + 1 == n]; vector ans(q, -1); vector> queries(n); REP(i, q) { if (h[b[i]] <= t[a[i]]) { ans[i] = 1; } else { queries[a[i]].emplace_back(i); } } vector ord(n); iota(ALL(ord), 0); ranges::sort(ord, {}, [&](const int i) -> pair { return {-t[i], h[i]}; }); vector seq; for (const int i : ord) { const int p = ssize(seq) - distance(seq.rbegin(), upper_bound(seq.rbegin(), seq.rend(), t[i])); if (p < seq.size()) { for (const int id : queries[i]) { if (t[seq.front()] < h[b[id]]) continue; int lb = 0, ub = p + 1; while (ub - lb > 1) { const int mid = midpoint(lb, ub); (h[b[id]] <= t[seq[mid]] ? lb : ub) = mid; } ans[id] = p - lb + 2; } } else { seq.clear(); } if (h[i] < t[i]) { while (seq.size() >= 2 && h[seq.end()[-2]] <= t[i]) seq.pop_back(); seq.emplace_back(i); } } REP(i, q) cout << ans[i] << '\n'; return 0; }