from typing import List, Tuple


def floorRange(n: int) -> List[Tuple[int, int, int]]:
    """
    将 [1,n] 内的数分成O(2*sqrt(n))段, 每段内的 n//i 相同

    Args:
        n (int): n>=1

    Returns:
        List[Tuple[int,int,int]]:
        每个元素为(left,right,div)
        表示 left <= i <= right 内的 n//i == div
    """
    res = []
    m = 1
    while m * m <= n:
        res.append((m, m, n // m))
        m += 1
    for i in range(m, 0, -1):
        left = n // (i + 1) + 1
        right = n // i
        if left <= right and res and res[-1][1] < left:
            res.append((left, right, n // left))
    return res


if __name__ == "__main__":
    # n = int(input())
    # print(floorRange(n))
    # [(1, 2, 9), (2, 3, 4), (3, 4, 3), (5, 10, 1)]

    # https://yukicoder.me/problems/no/1573
    # 约数总和
    MOD = 998244353
    n, m = map(int, input().split())
    res = 0
    for left, right, div in floorRange(n):
        right += 1
        lower = left
        higher = min(right - 1, m)
        if lower > higher:
            break
        x = div * (div + 1) // 2 + div
        y = (lower + higher) * (higher - lower + 1) // 2
        res += x * y
        res %= MOD
    print(res)