def main(): from math import sqrt,sin,cos,tan,ceil,radians,floor,gcd,exp,log,log10,log2,factorial,fsum from heapq import heapify, heappop, heappush from bisect import bisect_left, bisect_right from copy import deepcopy import copy import random from collections import deque,Counter,defaultdict from itertools import permutations,combinations from decimal import Decimal,ROUND_HALF_UP #tmp = Decimal(mid).quantize(Decimal('0'), rounding=ROUND_HALF_UP) from functools import lru_cache, reduce #@lru_cache(maxsize=None) from operator import add,sub,mul,xor,and_,or_,itemgetter INF = 10**18 mod1 = 10**9+7 mod2 = 998244353 #DecimalならPython #再帰ならPython!!!!!!!!!!!!!!!!!!!!!!!!!! ''' Xになんか足していけばよさそうやけど 約数の中で最小をかければいい オーダー死ぬのでは 約数でない最小の素数をかければよい 素数じゃなくても割り切れなければよい 高速素因数分解やるかー 各素因数で何回割れるか調べる 約数の個数を調べる 先に1~31までの素因数分解を済ませておく 比を求める ''' #[素因数, 何乗か] def factorization(n): arr = [] temp = n for i in range(2, int(-(-n**0.5//1))+1): if temp%i==0: cnt=0 while temp%i==0: cnt+=1 temp //= i arr.append([i, cnt]) if temp!=1: arr.append([temp, 1]) if arr==[]: arr.append([n, 1]) return arr prime = [2,3,5,7,11,13,17,19,23,29,31] ls = [[0]*32 for _ in range(32)] for i in range(2,32): tmp = factorization(i) for p,e in tmp: ls[i][p] = e for _ in range(int(input())): X = int(input()) s = X fact = [0]*32 for p in prime: while X%p == 0: X //= p fact[p] += 1 cnt = 1 for p in prime: cnt *= fact[p]+1 for i in range(2,32): cnt2 = cnt for p in prime: cnt2 //= fact[p]+1 cnt2 *= fact[p]+ls[i][p]+1 if cnt2 == cnt*2: print(s*i) break if __name__ == '__main__': main()