#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#undef _P
#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<to;x++)
#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
//-------------------------------------------------------

int K;
ll C[101000],T;
ll mo=1000000007;
const int NUM_=1000005;
static ll fact[NUM_+1],factr[NUM_+1],inv[NUM_+1];
ll num[1010000];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	inv[1]=fact[0]=factr[0]=1;
	for (int i=2;i<=NUM_;++i) inv[i] = inv[mo % i] * (mo - mo / i) % mo;
	for (int i=1;i<=NUM_;++i) fact[i]=fact[i-1]*i%mo, factr[i]=factr[i-1]*inv[i]%mo;
	
	cin>>K;
	if(K==1) return _P("1\n");
	
	FOR(i,K) cin>>C[i], T+=C[i];
	
	ll g=C[0];
	ll tot=0;
	FOR(i,K) g=__gcd(g,C[i]);
	
	for(i=1;i<=g;i++) if(g%i==0) {
		num[i]=fact[T/i];
		FOR(j,K) num[i] = num[i] * factr[C[j]/i] % mo;
		
		x=i;
		for(j=2;j*j<=x;j++) if(x%j==0) {
			num[i] -= num[j];
			while(x%j==0) x/=j;
		}
		if(x>1 && x!=i) num[i] -= num[x];
		
		num[i]=(num[i]%mo+mo)%mo;
		tot += num[i]/(T/i);
	}
	
	
	cout<<tot%mo<<endl;
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false);
	FOR(i,argc-1) s+=argv[i+1],s+='\n';
	FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	solve(); return 0;
}