#include #include #pragma GCC target("avx2") #pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") using namespace std; using namespace atcoder; #define rep(i, n) for (int i = 0; i < (int)(n); i++) #define repll(i, n) for (long long i = 0; i < (long long)(n); i++) #define rep2(i, n, m) for (int i = n; i < (int)(m); i++) #define repll2(i, n, m) for (long long i = n; i < (long long)(m); i++) #define all(v) v.begin(),v.end() using ll=long long; using ld=long double; using vi=vector; using vvi=vector; using vvvi=vector; using vl=vector; using vvl=vector; using vvvl=vector; using vld=vector; using vvld=vector; int dx[8]={1,0,-1,0,1,1,-1,-1}; int dy[8]={0,1,0,-1,1,-1,1,-1}; const double PI = acos(-1); //const ll MOD=1e9+7; //const ll MOD=998244353; const ll INF=(1LL<<60); const int INF2=(1<<30); //using mint=modint1000000007; using mint=modint998244353; /* divisor(n) 入力:整数 n 出力:nのすべての約数 計算量:O(√n) */ vector divisor(long long n) { vector ret; for (long long i = 1; i * i <= n; i++) { if (n % i == 0) { ret.push_back(i); if (i * i != n) ret.push_back(n / i); } } sort(ret.begin(), ret.end()); // 昇順に並べる return ret; } int main() { ios::sync_with_stdio(false); std::cin.tie(nullptr); int n,m;cin>>n>>m; vl arr(n); vl cnt(m+1,0); //cnt[i]=(arrのうち、iで割り切れるものの個数) rep(i,n){ cin>>arr[i]; auto d=divisor(arr[i]); for(auto v:d)cnt[v]++; } vector ans(m+1); for(int i=m;i>=1;i--){ ans[i]=mint(2).pow(cnt[i]); for(int j=2;j*i<=m;j++)ans[i]-=ans[j*i]; ans[i]--; } rep(i,m)cout<