#include #include using namespace std; using namespace atcoder; using ll=long long; using ld=long double; ld pie=3.141592653589793; ll inf=14449999999999994; ll mod=1000000007; ll modpow(ll x, ll n) { x = x%mod; if(n==0) return 1; //再帰の終了条件 else if(n%2==1) { return (x*modpow(x, n-1))%mod; //nが奇数ならnを1ずらす } else return modpow((x*x)%mod, n/2)%mod; //nが偶数ならnが半分になる } int main(){ ll s; cin >> s; for (ll o = 0; o < s; o++) { ll n,m,x; cin >> n >> m >> x; ll y=modpow(1+m,n); ll z=modpow(1-m,n); if (x==0) { ll ans=y+z; ans%=mod; ans+=mod; ans%=mod; ans*=inv_mod(2,mod); ans%=mod; cout << ans << endl; }else{ ll ans=y-z; ans%=mod; ans+=mod; ans%=mod; ans*=inv_mod(2,mod); ans%=mod; cout << ans << endl; } } }