N = int(input())

c, remainder = divmod(N, 36)

# NOTE: dict ではなく list にしたほうがカッコイイけど、
#       余りの値: a, b という対応にしたほうが分かりやすいと思ったので。
a, b = {
    1: (1, 2),
    2: (1, 3),
    3: (1, 4),
    4: (1, 5),
    5: (1, 6),
    6: (1, 7),
    7: (1, 8),
    8: (1, 9),
    9: (2, 3),
    10: (2, 4),
    11: (2, 5),
    12: (2, 6),
    13: (2, 7),
    14: (2, 8),
    15: (2, 9),
    16: (3, 4),
    17: (3, 5),
    18: (3, 6),
    19: (3, 7),
    20: (3, 8),
    21: (3, 9),
    22: (4, 5),
    23: (4, 6),
    24: (4, 7),
    25: (4, 8),
    26: (4, 9),
    27: (5, 6),
    28: (5, 7),
    29: (5, 8),
    30: (5, 9),
    31: (6, 7),
    32: (6, 8),
    33: (6, 9),
    34: (7, 8),
    35: (7, 9),
    0: (8, 9),
}[remainder]


def calculate_answer(a: int, b: int, c: int) -> int:
    x = 10 * a + b
    for _ in range(c):
        x = 10 * x + b
    return x


print(calculate_answer(a, b, c))