def f(n,m,xs)
ans="No"
if n==1 then
	return "Yes" if xs[0]==m
	return "No"
elsif n==2 then
	return "Yes" if xs[0]<=xs[1] && xs[1]==m
	return "No"
elsif xs[-1]==m then
	t=m-xs[0]
	return "No" if t<0
	xs=[t]+xs
	n=xs.size
	#
	(1..n-3).each{|i|
		t3=xs[i+1]-xs[i-1]
		t4=xs[i]-t3
		t5=xs[i+2]-t4
		t6=xs[i+1]-t5
		#p [t3,t4,t5,t6]
		return "No" if [t3,t4,t5,t6].any?{|e| e<0}
		xs[i]=t4
	}
	return "Yes"
end
return "No"
end
t=gets.to_i
t.times{
	a,b=gets.split(" ").map{|e| e.to_i}
	xs=gets.split(" ").map{|e| e.to_i}
	puts f(a,b,xs)
}