# 頂点削除、以下の方法でどうか # 次数管理して、まず次数3以上の頂点を次数降順で消していく # 1つの頂点を消すと辺のある先の次数も変わる # すべての次数が2以下になれば、すべての連結成分は道になる # 道の頂点数をkとすれば(k+1)//2の独立頂点ができる N = int(input()) edges = [[] for i in range(N+1)] degree = [0]*(N+1) for i in range(N-1): u, v = map(int, input().split()) edges[u].append(v) edges[v].append(u) degree[u] += 1 degree[v] += 1 degree_max = max(degree) removed = 0 for d in range(degree_max, 2, -1): for i in range(1, N+1): if degree[i] == d: removed += 1 temp = [] for nxt in edges[i]: temp.append(nxt) for nxt in temp: #print('d', d, 'i', i, 'nxt', nxt) degree[nxt] -= 1 degree[i] -= 1 edges[i].remove(nxt) edges[nxt].remove(i) #print(d, degree) #print(edges) class UnionFind(): def __init__(self, n): self.n = n self.parents = [-1] * n def find(self, x): if self.parents[x] < 0: return x else: self.parents[x] = self.find(self.parents[x]) return self.parents[x] def unite(self, x, y): x = self.find(x) y = self.find(y) if x == y: return if self.parents[x] > self.parents[y]: x, y = y, x self.parents[x] += self.parents[y] self.parents[y] = x def size(self, x): return -self.parents[self.find(x)] def same(self, x, y): return self.find(x) == self.find(y) def members(self, x): root = self.find(x) return [i for i in range(self.n) if self.find(i) == root] def roots(self): return [i for i, x in enumerate(self.parents) if x < 0] def group_count(self): return len(self.roots()) def all_group_members(self): group_members = defaultdict(list) for member in range(self.n): group_members[self.find(member)].append(member) return group_members def __str__(self): return '\n'.join(f'{r}: {m}' for r, m in self.all_group_members().items()) UF = UnionFind(N+1) for i in range(1, N+1): for nxt in edges[i]: if UF.same(i, nxt) == False: UF.unite(i, nxt) ans = -removed for r in UF.roots(): if r == 0: continue ans += (UF.size(r)+1)//2 print(ans)