#pragma GCC optimize("O3") #pragma GCC optimize("unroll-loops") #include // #include using namespace std; // using namespace atcoder; constexpr double time_limit = 1.9; constexpr int g = 14; constexpr int slow = 1000; constexpr int fast = 223; constexpr long long bonus = 50000; struct Input { int n, t; vector> ab, cd; void input() { cin >> n >> t; ab.resize(n); cd.resize(n); for (int i = 0; i < n; ++i) { int a, b, c, d; cin >> a >> b >> c >> d; ab[i] = {a - 1, b - 1}; cd[i] = {c - 1, d - 1}; } } }; long long expense(int people) { return floor(1e7 / sqrt(people)); } constexpr int inf = 1e9; constexpr int no_construction_turn = 350; constexpr int min_people = 25; constexpr int max_people = 100; constexpr int add_people = 20; struct Solver { int n, t; vector> ab, cd; vector> h, v; long long money = 1000000; int people = 1; int income = 0; int constructions = 0; Solver(const Input& input) { n = input.n; t = input.t; ab = input.ab; cd = input.cd; h = vector>(g, vector(g - 1, false)); v = vector>(g - 1, vector(g, false)); } void solve() { for (int turn = 0; turn < t; ++turn) { cin >> money >> people; //money += income; if (turn >= no_construction_turn) { cout << 3 << endl; money += bonus; } else if (money >= expense(people)) { auto [x, y, z, w] = choose_road(); if (x == -1) { cout << 3 << endl; money += bonus; continue; } cout << 1 << " " << x + 1 << " " << y + 1 << " " << z + 1 << " " << w + 1 << endl; ++constructions; money -= expense(people); income = calc_income(); } else if (people < min(max_people, min_people + add_people * constructions)) { cout << 2 << endl; ++people; } else { cout << 3 << endl; money += bonus; } } } vector> dijkstra(int sx, int sy) { vector> costs(g, vector(g, inf)); costs[sx][sy] = 0; priority_queue> todo; todo.push({0, sx, sy}); while (!todo.empty()) { auto [cost, x, y] = todo.top(); todo.pop(); cost = -cost; if (costs[x][y] < cost) { continue; } if (x > 0) { int c = v[x - 1][y] ? fast : slow; if (cost + c < costs[x - 1][y]) { costs[x - 1][y] = cost + c; todo.push({-(cost + c), x - 1, y}); } } if (x < g - 1) { int c = v[x][y] ? fast : slow; if (cost + c < costs[x + 1][y]) { costs[x + 1][y] = cost + c; todo.push({-(cost + c), x + 1, y}); } } if (y > 0) { int c = h[x][y - 1] ? fast : slow; if (cost + c < costs[x][y - 1]) { costs[x][y - 1] = cost + c; todo.push({-(cost + c), x, y - 1}); } } if (y < g - 1) { int c = h[x][y] ? fast : slow; if (cost + c < costs[x][y + 1]) { costs[x][y + 1] = cost + c; todo.push({-(cost + c), x, y + 1}); } } } return costs; } vector>>> all_costs() { vector>>> costs(g, vector>>(g)); for (int x = 0; x < g; ++x) { for (int y = 0; y < g; ++y) { costs[x][y] = dijkstra(x, y); } } return costs; } long long calc_income() { vector>>> costs = all_costs(); long long s = 0; for (int i = 0; i < n; ++i) { auto [a, b] = ab[i]; auto [c, d] = cd[i]; int cost = costs[a][b][c][d]; int j = 0; while ((cost - slow * j) % fast) { ++j; } s += (cost - slow * j) / fast; } return 60 * s; } tuple choose_road() { for (int y = 4; y < 9; ++y) { if (!h[7][y]) { h[7][y] = true; return {7, y, 7, y + 1}; } } for (int x = 4; x < 9; ++x) { if (!v[x][7]) { v[x][7] = true; return {x, 7, x + 1, 7}; } } for (int y = 4; y < 9; ++y) { if (!h[4][y]) { h[4][y] = true; return {4, y, 4, y + 1}; } } for (int x = 4; x < 9; ++x) { if (!v[x][4]) { v[x][4] = true; return {x, 4, x + 1, 4}; } } for (int y = 4; y < 9; ++y) { if (!h[10][y]) { h[10][y] = true; return {10, y, 10, y + 1}; } } for (int x = 4; x < 9; ++x) { if (!v[x][10]) { v[x][10] = true; return {x, 10, x + 1, 10}; } } for (int x = 4; x <= 10; x += 3) { for (int y = 0; y < g - 1; ++y) { if (!h[x][y]) { h[x][y] = true; return {x, y, x, y + 1}; } } } for (int y = 4; y <= 10; y += 3) { for (int x = 0; x < g - 1; ++x) { if (!v[x][y]) { v[x][y] = true; return {x, y, x + 1, y}; } } } return {-1, -1, -1, -1}; } }; int main() { Input input; input.input(); Solver solver(input); solver.solve(); cerr << solver.money << endl; return 0; }