#include //#include using namespace std; //using namespace atcoder; //using mint = modint1000000007; //const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; //const int INF = 1e9; const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define endl "\n" #define P pair> template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } const int dx[] = { 1,0,-1,0 }; const int dy[] = { 0,-1,0,1 }; int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int h, w; cin >> h >> w; int gx, gy; cin >> gx >> gy; gx--, gy--; vector a(h, vector(w)); rep(i, h)rep(j, w)cin >> a[i][j]; vector dp(250, vector(h, vector(w, LINF))); rep(i, 250) { long long k = i; dp[i][gx][gy] = k * k + a[gx][gy]; priority_queue, greater

> q; q.push({ dp[i][gx][gy], {gx, gy} }); while (!q.empty()) { auto tmp = q.top(); q.pop(); long long cost = tmp.first; int x = tmp.second.first; int y = tmp.second.second; if (cost > dp[i][x][y]) continue; rep(j, 4) { int nx = x + dx[j]; int ny = y + dy[j]; if ((nx < 0) || (nx >= h) || (ny < 0) || (ny >= w))continue; long long ncost = cost + k * k + a[nx][ny]; if (chmin(dp[i][nx][ny], ncost))q.push({ ncost, { nx, ny } }); } } } vector dp2(h, vector(w, LINF)); { set>st; dp2[gx][gy] = a[gx][gy]; st.insert({ gx,gy }); while (!st.empty()) { set>st2; for (auto e : st) { int x = e.first; int y = e.second; rep(j, 4) { int nx = x + dx[j]; int ny = y + dy[j]; if ((nx < 0) || (nx >= h) || (ny < 0) || (ny >= w))continue; if (LINF == dp2[nx][ny])st2.insert({ nx, ny }); if (!st2.count({ nx,ny })) continue; long long ncost = dp2[x][y] + a[nx][ny]; chmin(dp2[nx][ny],ncost); } } swap(st2, st); } } int q; cin >> q; while (q--) { int x, y; cin >> x >> y; x--, y--; long long k; cin >> k; if (k > 250) { long long ans = dp2[x][y]; long long d = abs(gx - x) + abs(gy - y) + 1; ans += k * k * d; cout << ans << endl; } else { cout << dp[k][x][y] << endl; } } return 0; }