#include <bits/stdc++.h>
#include <atcoder/all>
using namespace std;
using namespace atcoder;
using mint = modint1000000007;
const int mod = 1000000007;
//using mint = modint998244353;
//const int mod = 998244353;
//const int INF = 1e9;
//const long long LINF = 1e18;
#define rep(i, n) for (int i = 0; i < (n); ++i)
#define rep2(i,l,r)for(int i=(l);i<(r);++i)
#define rrep(i, n) for (int i = (n-1); i >= 0; --i)
#define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i)
#define all(x) (x).begin(),(x).end()
#define allR(x) (x).rbegin(),(x).rend()
#define endl "\n"
#define P pair<int,int>
template<typename A, typename B> inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; }
template<typename A, typename B> inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; }
//a /= osa_k[a]と a == 1になるまで続けると素因数分解に相当する
// osa_k法
int osa_k[3000006];
void sieve(int max = 3000006) {
	osa_k[1] = 1;
	for (int i = 2; i < max; ++i) {
		if (0 != osa_k[i])continue;
		osa_k[i] = i;
		for (int j = i * 2; j <= max; j += i) {
			if (0 == osa_k[j]) osa_k[j] = i;
		}
	}
}
int main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	long long h, w; cin >> h >> w;
	sieve();
	mint ans = 0;
	ans += (mint)h *(w - 1);
	ans += (mint)w *(h - 1);
	rep2(i, 1, h) {
		vector<int>v;
		int ci = i;
		while (ci != 1) {
			v.push_back(osa_k[ci]);
			ci /= osa_k[ci];
		}
		sort(all(v));
		v.erase(unique(all(v)), v.end());
		int sz = v.size();
		mint val0 = 0;
		mint val1 = 0;
		rep(j, 1 << sz) {
			int x = 1;
			int pc = 0;
			rep(k, sz) {
				if (1 & (j >> k)) {
					pc++;
					x *= v[k];
				}
			}
			mint s0 = (w - 1) / x;
			mint s1 = (x + x * s0) * s0 / 2;
			if (0 == pc % 2) {
				val0 += s0;
				val1 += s1;
			}
			else {
				val0 -= s0;
				val1 -= s1;
			}
		}
		ans += ((mint)h - i) * (val0 * w - val1) * 2;
	}
	cout << ans.val() << endl;
	return 0;
}