#include #include using namespace std; using namespace atcoder; namespace shobon { // Implement (union by size) + (path compression) // Reference: // Zvi Galil and Giuseppe F. Italiano, // Data structures and algorithms for disjoint set union problems struct dsu { public: dsu() : _n(0) {} explicit dsu(int n) : _n(n), parent_or_size(n, -1) {} int _n; std::vector parent_or_size; int merge(int a, int b) { assert(0 <= a && a < _n); assert(0 <= b && b < _n); int x = leader(a), y = leader(b); if (x == y) return x; if (-parent_or_size[x] < -parent_or_size[y]) std::swap(x, y); parent_or_size[x] += parent_or_size[y]; parent_or_size[y] = x; return x; } bool same(int a, int b) { assert(0 <= a && a < _n); assert(0 <= b && b < _n); return leader(a) == leader(b); } int leader(int a) { assert(0 <= a && a < _n); if (parent_or_size[a] < 0) return a; return parent_or_size[a] = leader(parent_or_size[a]); } int size(int a) { assert(0 <= a && a < _n); return -parent_or_size[leader(a)]; } std::vector> groups() { std::vector leader_buf(_n), group_size(_n); for (int i = 0; i < _n; i++) { leader_buf[i] = leader(i); group_size[leader_buf[i]]++; } std::vector> result(_n); for (int i = 0; i < _n; i++) { result[i].reserve(group_size[i]); } for (int i = 0; i < _n; i++) { result[leader_buf[i]].push_back(i); } result.erase( std::remove_if(result.begin(), result.end(), [&](const std::vector& v) { return v.empty(); }), result.end()); return result; } }; } // namespace atcoder typedef modint998244353 mint; typedef long long ll; int main(){ int n, q; cin >> n >> q; vector> stack; shobon::dsu uf(2*n); mint ans = mint(2).pow(n); mint inv2 = mint(2).inv(); for (int i=0; i> t; if (t == 2){ int x, y; cin >> x >> y; x--; y--; stack.push_back(pair(x, n+y)); stack.push_back(pair(y, n+x)); if (!uf.same(x, n+y)) ans *= inv2; uf.merge(x, n+y); uf.merge(y, n+x); if (uf.same(x, n+x)) ans = 0; if (uf.same(y, n+y)) ans = 0; }else if(t == 1){ int x,y; cin >> x >> y; x--; y--; stack.push_back(pair(x, y)); stack.push_back(pair(n+y, n+x)); if (!uf.same(x, y)) ans *= inv2; uf.merge(x, y); uf.merge(n+y, n+x); if (uf.same(x, n+x)) ans = 0; if (uf.same(y, n+y)) ans = 0; }else{ for (auto [u,v]: stack){ uf.parent_or_size[u] = -1; uf.parent_or_size[v] = -1; } stack.clear(); ans = mint(2).pow(n); } cout << ans.val() << endl; } }