#include #define all(v) v.begin(), v.end() #define rall(v) v.rbegin(), v.rend() #define rep(i,n) for(int i=0;i<(int)(n);i++) #define codefor int test;cin>>test;while(test--) #define INT(...) int __VA_ARGS__;in(__VA_ARGS__) #define LL(...) ll __VA_ARGS__;in(__VA_ARGS__) #define vector2d(type,name,h,...) vector>name(h,vector(__VA_ARGS__)) #define vector3d(type,name,h,w,...) vector>>name(h,vector>(w,vector(__VA_ARGS__))) using namespace std; using ll = long long; template using rpriority_queue = priority_queue, greater>; template istream& operator>>(istream& is, vector& vec) {for(T& x : vec)is >> x;return is;} template ostream& operator<<(ostream& os, const vector& vec) {if(vec.empty())return os;os << vec[0];for(auto it = vec.begin(); ++it!= vec.end();)os << ' ' << *it;return os;} void in(){} template void in(Head& head, Tail&... tail){cin >> head;in(tail...);} void out(){cout << '\n';} templatevoid out(const T& a){cout << a << '\n';} template void out(const Head& head,const Tail&... tail){cout << head << ' ';out(tail...);} const int INF = 1 << 30; const long long INF2 = 1ll << 60; template void chmax(T &a,const T b){if(b>a)a=b;} template void chmin(T &a,const T b){if(b struct prime_modint { using mint = prime_modint; unsigned int v; prime_modint() : v(0) {} prime_modint(unsigned int a) { a %= MOD; v = a; } prime_modint(unsigned long long a) { a %= MOD; v = a; } prime_modint(int a) { a %= (int)(MOD); if(a < 0)a += MOD; v = a; } prime_modint(long long a) { a %= (int)(MOD); if(a < 0)a += MOD; v = a; } static constexpr int mod() { return MOD; } mint& operator++() {v++; if(v == MOD)v = 0; return *this;} mint& operator--() {if(v == 0)v = MOD; v--; return *this;} mint operator++(int) { mint result = *this; ++*this; return result; } mint operator--(int) { mint result = *this; --*this; return result; } mint& operator+=(const mint& rhs) { v += rhs.v; if(v >= MOD) v -= MOD; return *this; } mint& operator-=(const mint& rhs) { if(v < rhs.v) v += MOD; v -= rhs.v; return *this; } mint& operator*=(const mint& rhs) { v = (unsigned int)((unsigned long long)(v) * rhs.v % MOD); return *this; } mint& operator/=(const mint& rhs) { return *this = *this * rhs.inv(); } mint operator+() const { return *this; } mint operator-() const { return mint() - *this; } mint pow(long long n) const { assert(0 <= n); mint r = 1, x = *this; while (n) { if (n & 1) r *= x; x *= x; n >>= 1; } return r; } mint inv() const { assert(v); return pow(MOD - 2); } friend mint operator+(const mint& lhs, const mint& rhs) { return mint(lhs) += rhs; } friend mint operator-(const mint& lhs, const mint& rhs) { return mint(lhs) -= rhs; } friend mint operator*(const mint& lhs, const mint& rhs) { return mint(lhs) *= rhs; } friend mint operator/(const mint& lhs, const mint& rhs) { return mint(lhs) /= rhs; } friend bool operator==(const mint& lhs, const mint& rhs) { return (lhs.v == rhs.v); } friend bool operator!=(const mint& lhs, const mint& rhs) { return (lhs.v != rhs.v); } friend std::ostream& operator << (std::ostream &os, const mint& rhs) noexcept { return os << rhs.v; } }; //using mint = prime_modint<1000000007>; using mint = prime_modint<998244353>; int main(){ ios::sync_with_stdio(false); cin.tie(0); codefor{ LL(n, x); string s = to_string(n); //桁数,フラグ,桁上がり回数,次で桁上がり必須か mint dp[s.size() + 1][8][s.size() + 1]; dp[0][3][0] = 1; dp[0][7][0] = 1; auto f2 = [&](int l1, int r1, int l2, int r2, int S){ int res = 0; res += ((l1 == r1) & (S & 1)); res += 2 * ((l2 == r2) & (S >> 1 & 1)); return res; }; for(int i = 0; i < s.size(); i++){ for(int j = 0; j < 8; j++){ int r1 = j & 1 ? s[i] - '0' : 9; int r2 = j >> 1 & 1 ? s[i] - '0' : 9; int f = j >> 2 & 1; //桁上がりするかしないか for(int k = 0; k < s.size(); k++){ for(int l1 = 0; l1 <= r1; l1++){ for(int l2 = 0; l2 <= r2; l2++){ if(l1 + l2 < 9){ if(f) continue; dp[i + 1][f2(l1, r1, l2, r2, j)][k] += dp[i][j][k]; dp[i + 1][f2(l1, r1, l2, r2, j) + 4][k] += dp[i][j][k]; }else if(l1 + l2 == 9){ if(f){ dp[i + 1][f2(l1, r1, l2, r2, j) + 4][k + 1] += dp[i][j][k]; }else{ dp[i + 1][f2(l1, r1, l2, r2, j)][k] += dp[i][j][k]; } }else{ if(!f) continue; dp[i + 1][f2(l1, r1, l2, r2, j)][k + 1] += dp[i][j][k]; dp[i + 1][f2(l1, r1, l2, r2, j) + 4][k + 1] += dp[i][j][k]; } } } } } } mint ans; for(int i = 0; i < 4; i++){ if(x <= s.size()) ans += dp[s.size()][i][x]; } out(ans); } }