#include //#include using namespace std; //using namespace atcoder; //using mint = modint1000000007; //const int mod = 1000000007; //using mint = modint998244353; //const int mod = 998244353; //const int INF = 1e9; //const long long LINF = 1e18; #define rep(i, n) for (int i = 0; i < (n); ++i) #define rep2(i,l,r)for(int i=(l);i<(r);++i) #define rrep(i, n) for (int i = (n-1); i >= 0; --i) #define rrep2(i,l,r)for(int i=(r-1);i>=(l);--i) #define all(x) (x).begin(),(x).end() #define allR(x) (x).rbegin(),(x).rend() #define endl "\n" #define P pair template inline bool chmax(A & a, const B & b) { if (a < b) { a = b; return true; } return false; } template inline bool chmin(A & a, const B & b) { if (a > b) { a = b; return true; } return false; } int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int n; cin >> n; long long l, r; cin >> l >> r; vectora(n); rep(i, n)cin >> a[i]; auto f = [&](long long mx)->long long { if (mx < 0)return 0; vectorneed(61, -1); rep(i, n - 1) { rrep(j, 61) { int x = 1 & (a[i + 0] >> j); int y = 1 & (a[i + 1] >> j); if (x == y)continue; if (-1 == need[60 - j]) need[60 - j] = x > y; else if (need[60 - j] != (x > y)) return 0; break; } } vector dp(62, vector(2));//未満が1 dp[0][0] = 1; rep(i, 61) { vector num; if (-1 == need[i]) num = { 1,0 }; else num = { need[i] }; rep(j, 2) { int k = 1 & (mx >> (60 - i)); rep(l, num.size()) { int nx = num[l]; if (!j && k < nx) continue; int nj = !(!j && (k == nx)); dp[i + 1][nj] += dp[i][j]; } } } return dp[61][1] + dp[61][0]; }; long long ans = f(r) - f(l - 1); cout << ans << endl; return 0; }