#include <iostream>
#include <vector>
#include <cmath>
#include <map>
#include <set>
#include <iomanip>
#include <queue>
#include <algorithm>
#include <numeric>
#include <deque>
#include <complex>

using namespace std;

template<class S, S (*op)(S, S), S (*e)()>struct SegTree {
    vector<S> seg;
    long long N = 1;

    SegTree (long long n) : SegTree(vector<S>(n, e())) {}
    SegTree (const vector<S> &v){
        long long n = v.size();
        while (N < n) N *= 2;
        seg.resize(N*2-1, e());
        for (long long i=0; i<n; i++) seg[i+N-1] = v[i];
        for (long long i=N-2; i>=0; i--){
            seg[i] = op(seg[i*2+1], seg[i*2+2]);
        }
    }

    void set(long long loc, S val){
        loc += N-1;
        seg[loc] = val;
        while (loc != 0){
            loc = (loc-1)/2;
            seg[loc] = op(seg[loc*2+1], seg[loc*2+2]);
        }
    }

    //op(a[l], ..., a[r])
    S prod (long long l, long long r) const{
        return _prod(l, r, 0, 0, N-1);
    }

    S all_prod() const{
        return seg[0];
    }

    S _prod (long long l, long long r, long long idx, long long bitl, long long bitr) const{
        if (r < bitl || l > bitr) return e();
        if (l <= bitl && bitr <= r) return seg[idx];

        long long bitm = (bitl+bitr)/2;
        return op(_prod(l, r, idx*2+1, bitl, bitm), _prod(l, r, idx*2+2, bitm+1, bitr));
    }

    S get (long long i) const{
        return seg[i+N-1];
    }

    void show() const{
        for (int i=N-1; i<N*2-1; i++) cout << seg[i] << " ";
        cout << endl;
    }
};

long long op(long long a, long long b){
    return max(a, b);
}

const long long INF = (1LL<<62) - 1;

long long e(){
    return -INF;
}

using ll = long long;
 
int main(){

    ll N, l=0, ans=0;
    cin >> N;
    vector<ll> A(N), B(N), x(N), y(N);
    for (int i=0; i<N; i++) cin >> A[i];
    for (int i=0; i<N; i++) cin >> B[i];

    for (int i=0; i<N; i++){
        x[i] = A[i]+B[i];
        y[i] = A[i]-B[i];
    }

    SegTree<long long, op, e> mi(y), pl(x);

    auto judge = [&](auto i, auto j){
        return (pl.prod(i, j-1) < A[j]+B[j]) && (mi.prod(i, j-1) < A[j]-B[j]);
    };

    for (int r=0; r<N; r++){
        while(l<r && !judge(l, r)) l++;
        if (judge(l, r)) ans += r-l;
    }

    cout << ans << endl;
    return 0;
}