#include <iostream>
#include <vector>
#include <cmath>
#include <map>
#include <set>
#include <iomanip>
#include <queue>
#include <algorithm>
#include <numeric>
#include <deque>
#include <complex>
#include <cassert>

using namespace std;
using ll = long long;

const ll modc = 998244353;
class mint {
    ll x;
public:
    mint(ll x=0) : x((x%modc+modc)%modc) {}
    mint operator-() const {
      return mint(-x);
    }
    mint& operator+=(const mint& a) {
        if ((x += a.x) >= modc) x -= modc;
        return *this;
    }
    mint& operator-=(const mint& a) {
        if ((x += modc-a.x) >= modc) x -= modc;
        return *this;
    }
    mint& operator*=(const  mint& a) {
        (x *= a.x) %= modc;
        return *this;
    }
    mint operator+(const mint& a) const {
        mint res(*this);
        return res+=a;
    }
    mint operator-(const mint& a) const {
        mint res(*this);
        return res-=a;
    }
    mint operator*(const mint& a) const {
        mint res(*this);
        return res*=a;
    }
    mint pow(ll t) const {
        if (!t) return 1;
        mint a = pow(t>>1);
        a *= a;
        if (t&1) a *= *this;
        return a;
    }
    mint inv() const {
        return pow(modc-2);
    }
    mint& operator/=(const mint& a) {
        return (*this) *= a.inv();
    }
    mint operator/(const mint& a) const {
        mint res(*this);
        return res/=a;
    }

    friend ostream& operator<<(ostream& os, const mint& m){
        os << m.x;
        return os;
    }

    friend istream& operator>>(istream& ip, mint&m) {
        ip >> m.x;
        return ip;
    }
};

int main(){

    ll N, X, Y;
    mint ans=0, a, b, bs=2;
    cin >> N >> X >> Y;
    vector<int> A(X), B(Y);
    for (int i=0; i<X; i++) cin >> A[i];
    for (int i=0; i<Y; i++) cin >> B[i];

    for (int i=0; i<19; i++){
        a = 0; b = 0;
        for (int j=0; j<X; j++) if (1<<i & A[j]) a+=1;
        for (int j=0; j<Y; j++) if (1<<i & B[j]) b+=1;
        vector<vector<mint>> dp(N+1, vector<mint>(2));
        dp[0][0] = 1;
        for (int j=1; j<=N; j++){
            dp[j][1] += dp[j-1][1] * X * b + dp[j-1][0] * a * b;
            dp[j][0] += dp[j-1][1] * X * (-b+Y) + dp[j-1][0] * (-a * b + X * Y);
        }
        ans += dp[N][1] * bs.pow(i); 
    }

    cout << ans << endl;
}