#include <bits/stdc++.h>
using namespace std;
typedef signed long long ll;

#define _P(...) (void)printf(__VA_ARGS__)
#define FOR(x,to) for(x=0;x<(to);x++)
#define FORR(x,arr) for(auto& x:arr)
#define FORR2(x,y,arr) for(auto& [x,y]:arr)
#define ALL(a) (a.begin()),(a.end())
#define ZERO(a) memset(a,0,sizeof(a))
#define MINUS(a) memset(a,0xff,sizeof(a))
template<class T> bool chmax(T &a, const T &b) { if(a<b){a=b;return 1;}return 0;}
template<class T> bool chmin(T &a, const T &b) { if(a>b){a=b;return 1;}return 0;}
//-------------------------------------------------------

int N;
ll K;
vector<ll> D;
const int mo=998244353;
int dp[1515];
int nex[1515][1515];

void solve() {
	int i,j,k,l,r,x,y; string s;
	
	cin>>N>>K;
	
	for(j=1;j*j<=K;j++) if(K%j==0) {
		D.push_back(j);
		if(j*j!=K) D.push_back(K/j);
	}
	
	sort(ALL(D));
	map<int,int> M;
	FOR(i,D.size()) M[D[i]]=i;
	
	FOR(i,D.size()) FOR(j,D.size()) nex[i][j]=M[__gcd(K,D[i]*D[j])];
	
	dp[0]=1;
	while(N--) {
		ll a;
		cin>>a;
		x=M[__gcd((ll)K,a)];
		for(i=D.size()-1;i>=0;i--) {
			(dp[nex[i][x]]+=dp[i])%=mo;
		}
	}
	
	cout<<dp[D.size()-1]-(K==1)<<endl;
	
	
	
}


int main(int argc,char** argv){
	string s;int i;
	if(argc==1) ios::sync_with_stdio(false), cin.tie(0);
	FOR(i,argc-1) s+=argv[i+1],s+='\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);
	cout.tie(0); solve(); return 0;
}