#include #pragma GCC optimize("Ofast") #pragma GCC optimize("unroll-loops") using namespace std; using std::cout; using std::cin; using std::endl; using ll=long long; using ld=long double; ll ILL=2167167167167167167; const int INF=2100000000; const int mod=998244353; #define rep(i,a,b) for (ll i=a;i using _pq = priority_queue, greater>; template ll LB(vector &v,T a){return lower_bound(v.begin(),v.end(),a)-v.begin();} template ll UB(vector &v,T a){return upper_bound(v.begin(),v.end(),a)-v.begin();} template bool chmin(T &a,const T &b){if(a>b){a=b;return 1;}else return 0;} template bool chmax(T &a,const T &b){if(a void So(vector &v) {sort(v.begin(),v.end());} template void Sore(vector &v) {sort(v.begin(),v.end(),[](T x,T y){return x>y;});} void yneos(bool a){if(a) cout<<"Yes\n"; else cout<<"No\n";} template void vec_out(vector &p){for(int i=0;i<(int)(p.size());i++){if(i) cout<<" ";cout< T vec_min(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmin(ans,x);return ans;} template T vec_max(vector &a){assert(!a.empty());T ans=a[0];for(auto &x:a) chmax(ans,x);return ans;} template T vec_sum(vector &a){assert(!a.empty());T ans=a[0]-a[0];for(auto &x:a) ans+=x;return ans;} int pop_count(long long a){int res=0;while(a){res+=(a&1),a>>=1;}return res;} void solve(); // oddloop int main() { ios::sync_with_stdio(false); cin.tie(nullptr); int t=1; //cin>>t; rep(i,0,t) solve(); } void solve(){ int N,M; cin>>N>>M; vector p(N); rep(i,0,N) cin>>p[i]; vector> m(N); vector> G(N); rep(i,0,M){ int a,b; cin>>a>>b; a--,b--; G[a].push_back(b); G[b].push_back(a); } vector>> g(2,vector>(N)); vector big(N); int B=100; rep(i,0,N){ if((int)(G[i].size())>=B) big[i]=1; } rep(i,0,N){ for(auto x:G[i]){ g[big[x]][i].push_back(x); } } rep(i,0,N){ for(auto x:g[0][i]) m[i][p[x]]++; } int Q; cin>>Q; rep(i,0,Q){ int x,y; cin>>x>>y; x--,y--; if(p[x]==p[y]){ cout<<"No\n"; continue; }else{ bool ok=0; for(auto a:g[1][x]){ if(p[a]==p[y]) ok=1; } if(m[x].count(p[y])) ok=1; if(ok){ cout<<"Yes\n"; if(!big[x]){ for(auto a:G[x]){ m[a][p[x]]--; m[a][p[y]]++; if(m[a][p[x]]==0) m[a].erase(p[x]); } } p[x]=p[y]; } else{ cout<<"No\n"; } } } }