#include #include #define rep(i,b) for(int i=0;i=0;i--) #define rep1(i,b) for(int i=1;i=x;i--) #define fore(i,a) for(auto& i:a) #define rng(x) (x).begin(), (x).end() #define rrng(x) (x).rbegin(), (x).rend() #define sz(x) ((int)(x).size()) #define pb push_back #define fi first #define se second #define pcnt __builtin_popcountll using namespace std; using namespace atcoder; using ll = long long; using ld = long double; template using mpq = priority_queue, greater>; template bool chmax(T &a, const T &b) { if (a bool chmin(T &a, const T &b) { if (b ll sumv(const vector&a){ll res(0);for(auto&&x:a)res+=x;return res;} bool yn(bool a) { if(a) {cout << "Yes" << endl; return true;} else {cout << "No" << endl; return false;}} #define dame { cout << "No" << endl; return;} #define dame1 { cout << -1 << endl; return;} #define cout2(x,y) cout << x << " " << y << endl; #define coutp(p) cout << p.fi << " " << p.se << endl; #define out cout << ans << endl; #define outd cout << fixed << setprecision(20) << ans << endl; #define outm cout << ans.val() << endl; #define outv fore(yans , ans) cout << yans << "\n"; #define outdv fore(yans , ans) cout << yans.val() << "\n"; #define coutv(v) {fore(vy , v) {cout << vy << " ";} cout << endl;} #define coutv2(v) fore(vy , v) cout << vy << "\n"; #define coutvm(v) {fore(vy , v) {cout << vy.val() << " ";} cout << endl;} #define coutvm2(v) fore(vy , v) cout << vy.val() << "\n"; using pll = pair;using pil = pair;using pli = pair;using pii = pair;using pdd = pair; using vi = vector;using vd = vector;using vl = vector;using vs = vector;using vb = vector; using vpii = vector;using vpli = vector;using vpll = vector;using vpil = vector; using vvi = vector>;using vvl = vector>;using vvs = vector>;using vvb = vector>; using vvpii = vector>;using vvpli = vector>;using vvpll = vector;using vvpil = vector; using mint = modint998244353; //using mint = modint1000000007; //using mint = dynamic_modint<0>; using vm = vector; using vvm = vector>; vector dx={1,0,-1,0,1,1,-1,-1},dy={0,1,0,-1,1,-1,1,-1}; ll gcd(ll a, ll b) { return a?gcd(b%a,a):b;} ll lcm(ll a, ll b) { return a/gcd(a,b)*b;} #define yes {cout <<"Yes"<; const int dig = 19; void solve(){ ll n; cin>>n; int x; cin>>x; vvvm dp(4, vvm(dig,vm(dig))); dp[3][0][0] = 1; string s = to_string(n); int k = sz(s); rep(ii,k){ vvvm tmp(4, vvm(dig,vm(dig))); swap(dp,tmp); int c = s[ii]-'0'; rep(is9,dig){ rep(i,dig){ rep(j,4){ rep(a,10){ if (j%2==1&&a>c) break; rep(b,10){ if (j>=2&&b>c) break; if (tmp[j][is9][i]==0) continue; int nd = i; int nis9 = is9; if (a+b>=10){ nd+=is9+1; nis9=0; }else if(a+b==9){ nis9++; }else{ nis9=0; } if (nd>=dig) continue; if (nis9>=dig) continue; int nj = 0; if (j==0){ nj = 0; }else if(j==1){ nj = 0; if (a==c) nj = 1; }else if(j==2){ nj = 0; if (b==c) nj = 2; }else{ if (a==c){ if (b==c){ nj = 3; }else{ nj = 1; } }else{ if (b==c) nj = 2; } } dp[nj][nis9][nd] += tmp[j][is9][i]; } } } } } } mint ans = 0; rep(i,4) rep(j,dig) ans += dp[i][j][x]; outm; return; } int main(){ ios::sync_with_stdio(false); cin.tie(0); int t = 1; cin>>t; rep(i,t){ solve(); } return 0; }